1884 United States presidential election in Arkansas

1884 United States presidential election in Arkansas
Cleveland 40–50% 50–60% 60–70% 70–80% 80–90% 90–100%	Blaine 50–60% 60–70% 70–80% 80–90% 90–100%
President before election; Chester A. Arthur; Republican	Elected President ; Grover Cleveland; Democratic

The 1884 United States presidential election in Arkansas took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. Arkansas voters chose seven electors to the Electoral College, which selected the president and vice president.

Arkansas voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 17.12%.

Results

1884 United States presidential election in Arkansas^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	72,734	57.83%	7	100.00%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	51,198	40.70%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	1,847	1.47%	0	0.00%
Total				125,779	100.00%	7	100.00%

This Arkansas elections-related article is a stub. You can help Wikipedia by expanding it.