This Left Feels Right Bon Jovi talde estatubatuarraren abesti arrakastatsuenak bertsio akustikoan biltzen dituen estudio albuma da. Diskoak ez zuen esperotako...

(\left\vert a\right\vert =\left\vert b\right\vert {\text{eta}}\left\vert b\right\vert =\left\vert c\right\vert )\Longrightarrow \left\vert a\right\vert...

{2n+1}{2}}\right)\right)\\&{}={\frac {1}{2}}\csc \left({\frac {1}{2}}\right)\left(\cos \left({\frac {1}{2}}\right)-\cos \left({\frac {2N+1}{2}}\right)\right).\end{aligned}}}...

{\begin{aligned}\left(100a+10b+c\right)\left({\bmod {9}}\right)&=100a\left({\bmod {9}}\right)+10b\left({\bmod {9}}\right)+c\left({\bmod {9}}\right)\\&=a\left[100\left({\bmod...

{\displaystyle \operatorname {tr} \left(A+B\right)=\operatorname {tr} \left(A\right)+\operatorname {tr} \left(B\right)} tr ⁡ ( r A ) = r ( tr ⁡ ( A ) )...

{Im} \left(z\right)=0} bada, orduan z ¯ = z {\displaystyle {\bar {z}}=z} | z ¯ | = | z | {\displaystyle \left|{\bar {z}}\right|=\left|z\right|} z z ¯...

{\displaystyle {A\ {\rm {sen}}\left(\omega x+\varphi \right)=M{\rm {sen}}}\left(\omega x\right)+N\cos \left(\omega x\right)} non A 2 = M 2 + N 2 {\displaystyle...

( x a ) 2 + ( y b ) 2 − z = 0 {\displaystyle \left({\frac {x}{a}}\right)^{2}+\left({\frac {y}{b}}\right)^{2}-z=0} a = b denean, paraboloide eliptikoa...

daukana: | x a | n + | y b | n = 1 {\displaystyle \left|{\frac {x}{a}}\right|^{n}\!+\left|{\frac {y}{b}}\right|^{n}\!=1} non n > 0 den, eta a eta b irudiaren...

Johnson. «Right-wing, rightist», A Political Glossary, Auburngo Unibertsitatearen webgunea, 2005. ↑ (Ingelesez) Bobbio, Norberto eta Allan Cameron, Left and...

08205746\mathrm {\left[{\frac {atm\cdot L}{mol\cdot K}}\right]} \\=62,36367\mathrm {\left[{\frac {mmHg\cdot L}{mol\cdot K}}\right]} \\=1,987207\mathrm {\left[{\frac...

\cos \left(\operatorname {arctg} \left(x\right)\right)={\sqrt {\frac {1}{1+x^{2}}}}=\cos \left(\arccos \left({\sqrt {\frac {1}{1+x^{2}}}}\right)\right)} θ...

5 ⁡ ( t 12 ) ) {\displaystyle x=\sin(t)\left(e^{\cos(t)}-2\cos(4t)-\sin ^{5}\left({t \over 12}\right)\right)} y = cos ⁡ ( t ) ( e cos ⁡ ( t ) − 2 cos...

{g(x)}{\left[f(x)\right]^{-1}}}=\left({\frac {\infty }{\infty }}\right)_{\mathrm {I} }=\lim _{x\to a}{\frac {g'(x)}{{\left(\left[f(x)\right]^{-1}\right)}'}}}...

Y={\frac {1}{Z}}={\frac {1}{R+jX}}=\left({\frac {R}{R^{2}+X^{2}}}\right)+j\left({\frac {-X}{R^{2}+X^{2}}}\right)=G+jB\,} edo B = I m ( Y ) = ( − X R...

\over 2}+\left({1 \over 2}\prod _{n=1}^{\infty }\left(1-{2 \over p_{n}^{2}}\right)\right)\\[4pt]&={{1} \over {2}}\left(1+\prod _{n=1}^{\infty }\left(1-{{2}...

( s − c ) {\displaystyle \displaystyle A={\sqrt {s\left(s-a\right)\left(s-b\right)\left(s-c\right)}}} , non a, b, eta c aldeen luzerak diren. Brahmagupta-ren...

{\displaystyle V=\left({\frac {1}{6}}\left(5+4{\sqrt {5}}\right)\right)a^{3}\approx 2{,}32405a^{3}} R = ( 1 2 11 + 4 5 ) a ≈ 2,232 95 a {\displaystyle R=\left({\frac...

Zatitzaile funtzioa edo Sigma funtzioa ( σ ( n ) {\displaystyle \sigma \left(n\right)} funtzioa) funtzio aritmetiko bat da, n zenbaki arruntaren zatitzaile...

⁡ n x | n | {\displaystyle \Omega =\arccos {{n_{x}} \over {\mathbf {\left|n\right|} }}} (bada n y > 0 {\displaystyle n_{y}>0\,} ) edo Ω = 2 π − arccos...

{\displaystyle A=\left(7+2{\sqrt {2}}+{\sqrt {3}}\right)a^{2}\approx 11,5605a^{2}} V = ( 1 + 2 2 3 ) a 3 ≈ 1 , 94281 a 3 {\displaystyle V=\left(1+{\frac {2{\sqrt...

sin ⁡ α {\displaystyle \left\vert {\vec {L}}\right\vert =\left\vert {\vec {r}}\right\vert \cdot \left\vert {\vec {p}}\right\vert \cdot \sin \alpha }...

024 447583 {\displaystyle l=2\cdot r\cdot \sin \left({\frac {1}{2}}\cdot {\frac {2\pi }{257}}\right)\simeq 0{,}024447583} Azalera: A = 257 ⋅ r 2 ⋅ sin...

ϕ + θ ) = sen ⁡ ( ϕ + θ ) cos ⁡ ( ϕ + θ ) {\displaystyle \tan \left(\phi +\theta \right)={\cfrac {\operatorname {sen}(\phi +\theta )}{\cos(\phi +\theta...

x ) = log ⁡ 1 p ( x ) {\displaystyle I\left(x\right)=-\log p{\left(x\right)}=\log {\dfrac {1}{p\left(x\right)}}} Grafikoan ikusten den bezala, x {\displaystyle...

{y}}}\left({\frac {1}{N}}\sum _{i=1}^{N}y_{i}^{1-\varepsilon }\right)^{1/(1-\varepsilon )}&\ \varepsilon \in \left[0,1\right)\cup \left(1,+\infty \right)\\1-{\frac...

^{2}Rr=\left(2\pi r\right)\left(2\pi R\right)\,} V = 2 π 2 R r 2 = ( π r 2 ) ( 2 π R ) . {\displaystyle V=2\pi ^{2}Rr^{2}=\left(\pi r^{2}\right)\left(2\pi...

{\displaystyle {\frac {a+b}{c}}={\frac {\cos \left({\frac {\alpha -\beta }{2}}\right)}{\sin \left({\frac {\gamma }{2}}\right)}}} eta: a − b c = sin ⁡ ( α − β 2 )...

+ z 2 b 2 = 1 {\displaystyle \left({\frac {x}{a}}\right)^{2}+\left({\frac {y}{a}}\right)^{2}+\left({\frac {z}{b}}\right)^{2}=1\quad \quad {\hbox{ edo...

\left({\frac {R-r}{r}}\theta \right)} y ( θ ) = ( R − r ) sin ⁡ θ − r sin ⁡ ( R − r r θ ) , {\displaystyle y(\theta )=(R-r)\sin \theta -r\sin \left({\frac...

{min} \left(\left\lfloor {\frac {I_{outhigh}}{I_{inhigh}}}\right\rfloor ,\left\lfloor {\frac {I_{outlow}}{I_{inlow}}}\right\rfloor \right)} (Non min...

000 09587 {\displaystyle l=2\cdot r\cdot \sin \left({\frac {1}{2}}\cdot {\frac {2\pi }{65.537}}\right)\simeq r\cdot 0{,}00009587} Azalera: A = 65.537...

betetzen dute: s 2 = ( r 1 − r 2 ) 2 + h 2 {\displaystyle s^{2}=\left(r_{1}-r_{2}\right)^{2}+h^{2}} Kono-enborraren alde-azalera oinarrien perimetroen batezbestekoa...

{\displaystyle \sum _{n=1}^{\infty }\left({\frac {a_{1}+a_{2}+\cdots +a_{n}}{n}}\right)^{p}<\left({\frac {p}{p-1}}\right)^{p}\sum _{n=1}^{\infty }a_{n}^{p}...

f_{j}=\sum _{k=0}^{n-1}x_{k}\cos \left[{\frac {\pi }{n}}\left(j+{\frac {1}{2}}\right)\left(k+{\frac {1}{2}}\right)\right]} DCT V-etik VIII-ra ere existitzen...

{\displaystyle {f(x):}\left.{\begin{matrix}\in \left[a,b\right],&{\mbox{jarraitua}}\\\in \left(a,b\right),&{\mbox{diferentziagarria}}\end{matrix}}\right\}{\Rightarrow...

| h 1 B 1 3 − h 2 B 2 3 | , {\displaystyle V=\left|{\frac {h_{1}B_{1}}{3}}-{\frac {h_{2}B_{2}}{3}}\right|,} non h 1 {\displaystyle h_{1}\,} eta h 2 {\displaystyle...

{\displaystyle \left(\sum _{k=1}^{n}|x_{k}+y_{k}|^{p}\right)^{1/p}\leq \left(\sum _{k=1}^{n}|x_{k}|^{p}\right)^{1/p}+\left(\sum _{k=1}^{n}|y_{k}|^{p}\right)^{1/p}}...

{2\sin \left({\frac {\alpha -\beta }{2}}\right)\cos \left({\frac {\alpha +\beta }{2}}\right)}{2\sin \left({\frac {\alpha +\beta }{2}}\right)\cos \left({\frac...

2 {\displaystyle {\begin{aligned}A&=3\cot \left({\frac {\pi }{12}}\right)a^{2}=3\left(2+{\sqrt {3}}\right)a^{2}\simeq 11,19615242\,a^{2}\end{aligned}}}...

{\displaystyle A=\left(3+{\frac {5{\sqrt {3}}}{2}}\right)a^{2}\approx 7,33013a^{2}} V = ( 5 3 2 ) a 3 ≈ 1 , 17851 a 3 {\displaystyle V=\left({\frac {5}{3{\sqrt...

7557613141 ⋅ a {\displaystyle r_{i}={\frac {a}{12}}{\sqrt {3}}\left(3+{\sqrt {5}}\right)\approx 0.7557613141\cdot a} Erdiko puntutik elkarren alboko bi...

top right, act six at bottom right, act seven at top left, act eight at bottom left Acts 1-4 of the Kanadehon Chūshingura with act one at top right, act...

{\displaystyle \varepsilon \left[\Psi \right]={\frac {\left\langle \Psi |{\hat {H}}|\Psi \right\rangle }{\left\langle \Psi \mid \Psi \right\rangle }}.} Bariazio...

{\displaystyle \left(\nabla _{\mathbf {v} }f\right)_{p}=\left(f\circ \phi \right)'\left(0\right)=\lim _{t\to 0}{\frac {f\left[\phi \left(t\right)\right]-f\left[p\right]}{t}}...

:<math>\left ( {x^2 \over x^3 +1} \right ) ^\prime = { \left ( x^3 +1 \right ) \left ( x^2 \right )^\prime - \left ( x^2 \right ) \left ( x^3 +1 \right ) ^\prime...

x 1 + x 2 2 , y 1 + y 2 2 ) {\displaystyle \left({\frac {x_{1}+x_{2}}{2}},{\frac {y_{1}+y_{2}}{2}}\right)} Espazioan ere definitzen da bi puntuen arteko...

\left(\left\{a,b\right\},\left\{\left(a,2\right),\left(b,1\right)\right\}\right)} legez definitzen da eta { a , b } {\displaystyle \left\{a,b\right\}}...

sin ⁡ α {\displaystyle \left\vert {\vec {M}}\right\vert =\left\vert {\vec {r}}\right\vert \cdot \left\vert {\vec {F}}\right\vert \cdot \sin \alpha }...

{\displaystyle Funtzioa\left\{{\begin{array}{l}Jarraitua\left\{{\begin{array}{l}Deribagarria\\Ez-deribagarria\end{array}}\right.\\Etena\left...

}}a_{k}[n]\cos \left({\frac {2\pi f_{0}}{F_{\mathrm {s} }}}kn\right)-b_{k}[n]\sin \left({\frac {2\pi f_{0}}{F_{\mathrm {s} }}}kn\right)} edo s [ n ] =...

_{0}^{\left(1-D\right)T}\operatorname {d} I_{\text{L}}=\int _{0}^{\left(1-D\right)T}{\frac {V_{o}\,\operatorname {d} t}{L}}={\frac {V_{o}\left(1-D\right)T}{L}}}...

e − x / a ) , {\displaystyle y=a\,\cosh \left({x \over a}\right)={a \over 2}\,\left(e^{x/a}+e^{-x/a}\right),\,} non cosh kosinu hiperbolikoa den. kurba...

_{x}={\cfrac {1}{E}}\left[\sigma _{x}-\nu \left(\sigma _{y}+\sigma _{z}\right)\right]\\\varepsilon _{y}={\cfrac {1}{E}}\left[\sigma _{y}-\nu \left(\sigma _{x}+\sigma...

\left({\frac {R+r}{r}}\theta \right)} y ( θ ) = ( R + r ) sin ⁡ θ − r sin ⁡ ( R + r r θ ) , {\displaystyle y(\theta )=(R+r)\sin \theta -r\sin \left({\frac...

{\displaystyle G^{2}(\omega )=\left|H(j\omega )\right|^{2}={\frac {G_{0}^{2}}{1+\left({\frac {\omega }{\omega _{c}}}\right)^{2n}}}} non n = iragazkiaren...

right|\left.{\begin{matrix}2\\-6\\1\end{matrix}}\right)=E_{31}(-2)\left({\begin{matrix}1&1&1\\0&-1&-2\\0&-1&0\end{matrix}}\right|\left...

{\displaystyle P\left(G\right)=P\left(G\mid O_{1}\right)\cdot P\left(O_{1}\right)+P\left(G\mid O_{2}\right)\cdot P\left(O_{2}\right)=\left({\frac {3}{5}}\cdot...

{\left({\frac {\partial S}{\partial T}}\right)} _{V}{d}\!T+\int _{V_{0}}^{V}\operatorname {\left({\frac {\partial S}{\partial V}}\right)} _{T}{d}\...

{1}{2}}\left(A+A^{T}\right)+{\frac {1}{2}}\left(A-A^{T}\right)} non zati simetrikoa hau den 1 2 ( A + A T ) {\displaystyle {\frac {1}{2}}\left(A+A^{T}\right)}...

1 m 2 + 1 ) , {\displaystyle \left(x_{1},y_{1}\right)\ =\left({\frac {-b_{1}m}{m^{2}+1}},{\frac {b_{1}}{m^{2}+1}}\right)\,,} eta ( x 2 , y 2 )   = ( −...

( x ) + i sin ⁡ ( x ) {\displaystyle e^{ix}=\cos \left(x\right)+i\,\operatorname {sin} \left(x\right)} , non : x zenbaki erreala den; e logaritmo naturalaren...

{{\mbox{d}}\left(f(x)\right)}{{\mbox{d}}x}}\left.{\!\!{\frac {}{}}}\right|_{x=a}=\left({\frac {{\mbox{d}}\left(f(x)\right)}{{\mbox{d}}x}}\right)(a)} Aldagai...

={\begin{cases}\arctan \left({\frac {\sqrt {x^{2}+y^{2}}}{z}}\right)&z>0\\{\frac {\pi }{2}}&z=0\\\pi +\arctan \left({\frac {\sqrt {x^{2}+y^{2}}}{z}}\right)&z<0\end{cases}}\qquad...

= 0 {\displaystyle \left({\partial P\; \over \partial v\;}\right)_{T=T_{c}}=0} ( ∂ 2 P ∂ v 2 ) T = T c = 0 {\displaystyle \left({\partial ^{2}P\; \over...

\varepsilon _{0}c}}\left({\dot {\beta }}^{2}+{\frac {\left({\boldsymbol {\beta }}\cdot {\dot {\boldsymbol {\beta }}}\right)^{2}}{1-\beta ^{2}}}\right),} non β =...

{\displaystyle \{\left(1,1\right)\left(11\right)\}} Segre motakoak eta S O ( 1 , 1 ) × S O ( 2 ) {\displaystyle SO\left(1,1\right)\times SO\left(2\right)} isotropia...

bakarreko multzoa elementu bakar batek osatzen duen multzoa da. Honela idazten da: : E = { a } {\displaystyle E=\left\{a\right\}} . Datuak: Q1165112...

{\displaystyle f(x;p)=\left\{{\begin{matrix}p&x=1{\mbox{ bada }},\\1-p&x=0{\mbox{ bada }},\\0&{\mbox{ bestela.}}\end{matrix}}\right.} Probabilitate funtzioa...

+ b ) ⋅ c {\displaystyle \,\!\left({a+b}\right)\cdot c} edo c ⋅ ( a + b ) {\displaystyle \,\!c\cdot \left({a+b}\right)} Alderantzizko poloniar notazioa...

\theta -h\cos \left({a+b \over b}\theta \right)} y = ( a + b ) sin ⁡ θ − h sin ⁡ ( a + b b θ ) {\displaystyle y=(a+b)\sin \theta -h\sin \left({a+b \over b}\theta...

d f = 0 {\displaystyle t\cos \left({\frac {d\alpha }{2}}\right)-\left(t+dt\right)\cos \left({\frac {d\alpha }{2}}\right)+df=0} Cosinuaren propietateez...

{\begin{aligned}P(E)&=\left({\frac {1}{2}}\right)^{N}\times \left({\frac {1}{2}}\right)^{N-k}\times {\frac {(2N-k)!}{N!(N-k)!}}\times {\frac {1}{2}}\\&=\left({\frac...

{V_{P}I_{P}}{2}}\left\{3\cos \varphi +\left[\cos \left(2\omega t-\varphi \right)+\cos \left(2\omega t-{\frac {4}{3}}\pi -\varphi \right)+\cos \left(2\omega t-{\frac...

\left({cf}\right)'=cf'} ( f + g ) ′ = f ′ + g ′ {\displaystyle \left({f+g}\right)'=f'+g'} ( f − g ) ′ = f ′ − g ′ {\displaystyle \left({f-g}\right)'=f'-g'}...

\operatorname {DAME} =\operatorname {mediana} _{i}\left(\ \left|X_{i}-\operatorname {mediana} _{j}(X_{j})\right|\ \right)\,} Hau da, medianarako desbideratze edo...

{d^{4}f}{dg^{4}}}\left({\frac {dg}{dx}}\right)^{4}+6{\frac {d^{3}f}{dg^{3}}}\left({\frac {dg}{dx}}\right)^{2}{\frac {d^{2}g}{dx^{2}}}+{\frac {d^{2}f}{dg^{2}}}\left\{4{\frac...

− b ) ( s − c ) {\displaystyle {A}zalera={\sqrt {s\left(s-a\right)\left(s-b\right)\left(s-c\right)}}} non s triangeluaren sasiperimetroa da s = a + b...

{\displaystyle {\bar {V}}_{L1}=D\cdot V_{i}+\left(1-D\right)\cdot \left(V_{i}-V_{C}\right)=\left(V_{i}-(1-D)\cdot V_{C}\right)} (7) V ¯ L 2 = D ( V o + V C ) + (...

{\displaystyle \left\vert a_{n}-a_{m}\right\vert =\left\vert a_{n}-l+la_{m}\right\vert \leq \left\vert a_{n}-l\right\vert +\left\vert a_{m}-l\right\vert <{\tfrac...

{\mu \ {\vec {m}}\times ({\vec {r}}-{\vec {r}}')}{4\pi \ \left\Vert {\vec {r}}-{\vec {r}}'\right\|^{3}}}} eta eremu magnetiko dipolarra, hau izango da: B...

{\displaystyle \theta +\sin \theta \cos \theta +2\sin \theta =\left(2+{\frac {\pi }{2}}\right)\sin \varphi } Newtonen metodoa erabiliz kalkula daiteke θ....

… , ∂ f ∂ x n ) . {\displaystyle \nabla f=grad\ f\ =\left({\frac {\partial f}{\partial x_{1}}},\dots ,{\frac {\partial f}{\partial x_{n}}}\right).}...

{\displaystyle \lim _{n\rightarrow \infty }{n! \over {\sqrt {2\pi n}}\;\left({\frac {n}{e}}\right)^{n}}=1} Beraz, esan dezakegu n zenbaki altu baten faktorialaren...

y = b   s e n   t } {\displaystyle \left.{\begin{matrix}x=&a\ \cos \ t\\y=&b\ \mathrm {sen} \ t\end{matrix}}\right\}} Bere ebolutaren ekuazioa hau da:...

energia bereko fotoia. h v = | E n − E n ′ | {\displaystyle hv=\left\vert E_{n}-E_{n}'\right\vert } Hidrogenoaren espektro deritzo, beraz, hidrogenoak igorritako...

{\displaystyle (x_{1}+\left\vert m\right\vert Z,y_{1}+\left\vert m\right\vert Z)=(x_{2}+\left\vert m\right\vert Z,y_{2}+\left\vert m\right\vert Z)} , honela...

θ 2 ) . {\displaystyle ds^{2}=\left(1-{\frac {r_{\text{s}}}{r}}\right)\,dt^{2}-\left(1-{\frac {r_{\text{s}}}{r}}\right)^{-1}\,dr^{2}-r^{2}(\sin ^{2}\theta...

_{n\rightarrow \infty }\left[\sum _{k=1}^{n}{\frac {1}{k}}-\ln(n)\right]=\int _{1}^{\infty }\left({1 \over \lfloor x\rfloor }-{1 \over x}\right)\,dx} Gutxi gorabeherako...

) . {\displaystyle \phi _{X}\left(u;\mu ,\Sigma \right)=\exp \left(i\mu ^{\top }u-{\frac {1}{2}}u^{\top }\Sigma u\right).} Σ {\displaystyle \Sigma } matrize...

}{2}}\right)}{\tan \left({\frac {\beta +\gamma }{2}}\right)}},\quad {\frac {a-c}{a+c}}={\frac {\tan \left({\frac {\alpha -\gamma }{2}}\right)}{\tan \left({\frac...

p={\frac {2l}{t\pi }}-{\frac {2}{t\pi }}\left\{{\sqrt {l^{2}-t^{2}}}+t\sin ^{-1}\left({\frac {t}{l}}\right)\right\}+1.} Datuak: Q1753097 Multimedia: Buffon's...

− T ) V ( 2 3 ) ) {\displaystyle \gamma =\left({\frac {k(T_{c}-T)}{V^{\left({\frac {2}{3}}\right)}}}\right)} Adierazpenean V-k likidoaren masa molarra...

{\displaystyle f(x;\lambda )=\left\{{\begin{matrix}\lambda e^{-\lambda x},&\;x\geq 0,\\0,&\;x<0.\end{matrix}}\right.} Ohikoa da dentsitate-funtzioa...

L_{pres}=10\cdot \log _{10}\left(antilog\left({\frac {X_{1}}{10}}\right)+antilog\left({\frac {X_{2}}{10}}\right)+...\right)} (dB) Zeinetan L p r e s {\displaystyle...

B_{2}=\left({\frac {1}{3}}+{\frac {1}{5}}\right)+\left({\frac {1}{5}}+{\frac {1}{7}}\right)+\left({\frac {1}{11}}+{\frac {1}{13}}\right)+\left({\frac...

{\displaystyle V_{out}=V_{2}\left({\left(R_{3}+R_{1}\right)R_{4} \over \left(R_{4}+R_{2}\right)R_{1}}\right)-V_{1}\left({R_{3} \over R_{1}}\right)} Vin seinalea integratu...

{\displaystyle ax^{2}+bx+c=\left(x-{\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}\right)\left(x-{\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}\right)=0} Soluzioa bakarra bada...

{\displaystyle {\begin{aligned}\left]a,b\right[&=\{x\,|\,a<x<b\},\\\left[a,b\right[&=\{x\,|\,a\leq x<b\},\\\left]a,b\right]&=\{x\,|\,a<x\leq b\},\\{}[a,b]&=\{x\...

ds^{2}=-c^{2}\,{d\tau }^{2}=-\left(1-{\frac {r_{\mathrm {s} }}{r}}\right)c^{2}\,dt^{2}+\left(1-{\frac {r_{\mathrm {s} }}{r}}\right)^{-1}\,dr^{2}+r^{2}(d\theta...

}{~\hbar ^{2}\left|{\vec {p}}-{\vec {p}}'\right|~}}\,\int \limits _{0}^{\infty }r\,V(r)\,\sin {\left(\left|{\vec {p}}-{\vec {p}}'\right|\,r\,\right)}~\operatorname...

( t 2 ) ) {\displaystyle V(t)=(a(1+\cos(t)),a\sin(t),2a\sin \left({\frac {t}{2}}\right))} edo V ( t ) {\displaystyle V(t)} = { x = a ( 1 + cos ⁡ ( t...

Commentary: The Contentious Magazine that Transformed the Jewish Left Into the Neoconservative Right. . Datuak: Q192139 Multimedia: Neoconservatism / Q192139...

{a_{0}}{2}}+\sum _{n=1}^{\infty }\left[a_{n}\cos \left({\frac {2n\pi }{T}}t\right)+b_{n}\sin \left({\frac {2n\pi }{T}}t\right)\right]} non a 0 {\displaystyle a_{0}}...

{7}{2}}\quad \Longrightarrow \quad M={\sqrt {5\left[\left({\frac {p_{0}}{p}}\right)^{\frac {2}{7}}-1\right]}}} Hala ere, formula hau abiadura txikientzat...

j = 1 n s j ) {\displaystyle f_{i}(s)={\tilde {f}}_{i}\left(s_{i},\sum _{j=1}^{n}s_{j}\right)} Hau da, joko agregatiboentzat sari-funtzioak jokalarien...

( 20.000 20 ) = 9.965  zortzidun {\displaystyle \log _{2}\left({\frac {20.000}{20}}\right)=9.965{\text{ zortzidun}}} ↑ Euskalterm: [Musika Hiztegia]...

{1}{2\alpha ^{s}}}+2\int _{0}^{\infty }{\frac {\sin \left(s\arctan \left({\frac {y}{\alpha }}\right)\right)}{(y^{2}+\alpha ^{2})^{\frac {s}{2}}}}{\frac {dy}{e^{2\pi...

-\lambda _{0}\\y&=\ln {\left[\tan {\left({\frac {\pi }{4}}+{\frac {\phi }{2}}\right)}\right]}\\&={\frac {1}{2}}\ln {\left({\frac {1+\mathrm {sen} \...

4 π ( 10 800 π ) 2 = 466 560 000 π ≈ {\displaystyle 4\pi \left({\frac {10\,800}{\pi }}\right)^{2}={\frac {466\,560\,000}{\pi }}\approx } 148510660 dira...

v ∈ W } {\displaystyle U\cap W=\left\{\mathbf {v} \in V\colon \mathbf {v} \in U\ {\text{eta}}\ \mathbf {v} \in W\right\}} Bi azpiespazioren arteko ebakidura...

_{-2}^{2}\left\vert 4-x^{2}-0\right\vert dx=2\int _{0}^{2}4-x^{2}dx=2[4x-\left({\frac {x^{3}}{3}}\right)]_{0}^{2}=2\left[8-{\frac {2^{3}-0}{3}}\right]=\left({\frac...

_{d}=\left\{U\subseteq X:\forall x\in U,\exists \epsilon >0:B(x,\epsilon )\subseteq U\right\}\ non\ B(x,\epsilon )=\left\{y\in X:d(x,y)<r\right\}} Izan...

r ( 1 − cos ⁡   t ) {\displaystyle \left\{{\begin{matrix}x(t)=r(t-\sin \ t)\\y(t)=r(1-\cos \ t)\end{matrix}}\right.} non r zirkunferentzia sortzaileko...

{\textstyle {\begin{cases}x'=\gamma \left(x-vt\right)\\y'=y\\z'=z\\t'=\gamma \left(t-{\frac {vx}{c^{2}}}\right)\end{cases}}} Hemen v {\displaystyle v}...

_{-1}^{1}\left(10t^{3}+17t^{2}-{7 \over 9}t-{17 \over 3}\right)\,dt=\left[{5 \over 2}t^{4}+{17 \over 3}t^{3}-{7 \over 18}t^{2}-{17 \over 3}t\right]_{-1}^{1}}...

+d\cos \left({R-r \over r}\theta \right)} y ( θ ) = ( R − r ) sin ⁡ θ − d sin ⁡ ( R − r r θ ) . {\displaystyle y(\theta )=(R-r)\sin \theta -d\sin \left({R-r...

Coldplayren zuzeneko lehen diskoan (Live 2003) agertu zen abestia. LeftRightLeftRightLeft musika-bandaren albumean ere agertu zen. Coldplay taldeko Clocks...

 bada  . {\displaystyle -\left({\frac {a}{b}}\right)={\frac {-a}{b}}={\frac {a}{-b}}\quad {\mbox{eta}}\quad \left({\frac {a}{b}}\right)^{-1}={\frac {b}{a}}...

\operatorname {P} \left(T\geq 1000\right)=\operatorname {P} \left(|T-224.95|\geq 775.05\right)=\operatorname {P} \left(|T-224.95|\geq 50\times 15.5\right)\leq {\frac...

{1-{\frac {1}{c^{2}}}\left[\left({\frac {dx}{dt}}\right)^{2}+\left({\frac {dy}{dt}}\right)^{2}+\left({\frac {dz}{dt}}\right)^{2}\right]}}dt} Ekuazio hori...

{\displaystyle \alpha =\left(1+\left(0.48508+1.55171\,\omega -0.15613\,\omega ^{2}\right)\left(1-T_{r}^{\,0.5}\right)\right)^{2}} T r = T T c {\displaystyle...

{\displaystyle \left(\int \left|f(x)+g(x)\right|^{p}\,dx\right)^{1/p}\leq \left(\int \left|f(x)\right|^{p}\,dx\right)^{1/p}+\left(\int \left|g(x)\right|^{p}\,dx\right)^{1/p}...

\mathbf {1} _{A}(x)=\left\{{\begin{matrix}1&{\mbox{baldin eta}}\ x\in A,\\0&{\mbox{baldin eta}}\ x\notin A.\end{matrix}}\right.} Adibidez, bitez X =...

{\begin{aligned}{\bar {p}}(n)&=1\times \left(1-{\frac {1}{365}}\right)\times \left(1-{\frac {2}{365}}\right)\cdots \left(1-{\frac {n-1}{365}}\right)\\&={365\times 364\cdots...

funtzioa ( a + b 2 , f ( a + b 2 ) ) {\displaystyle \left({\frac {a+b}{2}},f\left({\frac {a+b}{2}}\right)\right)} puntutik pasatzen bada, metodo horri erdiko...

osatzen. ( a ˙ a ) 2 = 8 π G 3 ρ − K c 2 a 2 {\displaystyle \left({\frac {\dot {a}}{a}}\right)^{2}={\frac {8\pi G}{3}}\rho -K{\frac {c^{2}}{a^{2}}}} a ¨...

V = 1 4 ( 2 2 + 3 ) a 3 {\displaystyle V={\frac {1}{4}}\left(2{\sqrt {2}}+{\sqrt {3}}\right)a^{3}} Prisma triangeluar trigehituaren duala 5. ordenako...

∈ R 3 | x 2 + y 2 ≤ x } {\displaystyle \left\{(x,y,z)\in \mathbb {R} ^{3}\,{\big |}\,x^{2}+y^{2}\leq x\right\}} Gorputzaren bolumena formula honen bidez...

{(-1)^{n}}{2^{10n}}}\,\left(-{\frac {2^{5}}{4n+1}}\right.&{}-{\frac {1}{4n+3}}+{\frac {2^{8}}{10n+1}}-{\frac {2^{6}}{10n+3}}\left.{}-{\frac {2^{2}}{10n+5}}-{\frac...

{\displaystyle A\thicksim B} edo | A | = | B | {\displaystyle \left\vert A\right\vert =\left\vert B\right\vert } A eta B multzoak ekipotenteak izateak erlazio bat...

P S ) a n t ( P S ) i s o {\displaystyle G={\left({P \over S}\right)_{ant} \over {\left({P \over S}\right)_{iso}}}} Honako hau da uhin elektromagnetiko...

}=R_{1}+\left[\left(R_{2}+R_{3}\right)\|R_{4}\right)]} = 1 k Ω + [ ( 1 k Ω + 1 k Ω ) ‖ 2 k Ω ) ] {\displaystyle =1\,\mathrm {k} \Omega +\left[\left(1\,\mathrm...

}\left({\frac {f(x)}{g(x)}}\right)=l\Longleftrightarrow \left[\forall \varepsilon >0:\exists M>0,x>M\Rightarrow \left\vert {\frac {f(x)}{g(x)}}-l\right\vert...

θ / 2 ) | 1 ⟩ {\displaystyle \left|\psi \right\rangle =\mathrm {e} ^{\mathrm {i} \phi /2}\cos(\theta /2)\left|0\right\rangle +\mathrm {e} ^{-\mathrm...

1 n a k ) a n + 1 {\displaystyle \prod _{k=1}^{n+1}a_{k}=\left(\prod _{k=1}^{n}a_{k}\right)a_{n+1}} Biderkaria beste berdintasun garrantzitsu batzuk definitzeko...

t e a T = K o n s t a n t e a } ⟶ P 1 ⋅ V 1 = P 2 ⋅ V 2 {\displaystyle \left.{\begin{array}{l}{\cfrac {P_{1}\cdot V_{1}}{T_{1}\cdot n_{1}}}={\cfrac {P_{2}\cdot...

zorizko aldagai baterako: M X ( t ) := E ( e t X ) , t ∈ R , {\displaystyle M_{X}(t):=E\left(e^{tX}\right),\quad t\in \mathbb {R} ,} Datuak: Q535587...

) 2 + a 3 ( x − c ) 3 + … {\displaystyle \sum _{n=0}^{\infty }a_{n}\left(x-c\right)^{n}=a_{0}+a_{1}(x-c)^{1}+a_{2}(x-c)^{2}+a_{3}(x-c)^{3}+\ldots } Askotan...

0}{\frac {\Delta y}{\Delta x}}={\frac {\mathrm {d} y}{\mathrm {d} x}}=f'\left(x\right).} Notazio honek katearen erregela eta deribatu partzialak modu ulergarrian...

\varphi \ d\varphi \left[{\frac {\rho ^{3}}{3}}\right]_{2}^{3}={\Big [}\sin \varphi {\Big ]}_{0}^{\pi }\ \left(9-{\frac {8}{3}}\right)=0.} R 3 {\displaystyle...

orduan m! < n! izango da. n ! < ( n + 1 2 ) n {\displaystyle n!<\left({\frac {n+1}{2}}\right)^{n}} edozein n > 1 -entzako. m < n bada, orduan lehenengo propietatea...

\lim _{n\rightarrow \infty }\operatorname {P} \left(\left|{\overline {X}}_{n}-\mu \right|<\varepsilon \right)=1.} Datuak: Q207952 Multimedia: Law of large...

| t 1 − t 2 | {\displaystyle d(\gamma (t_{1}),\gamma (t_{2}))=v\left|t_{1}-t_{2}\right|} betetzen den. Honek geodesiken kontzeptua orokortzen du riemanndar...

≤ σ 2 ϵ 2 . {\displaystyle \forall \epsilon >0,\ \ P\left(\left|X-\mu \right|\geq \epsilon \right)\leq {\frac {\sigma ^{2}}{\epsilon ^{2}}}.} batezbestekoaren...

{df(v) \over dv}=-8\pi \left({m \over 2\pi k_{B}T}\right)^{3 \over 2}ve^{{-mv^{2}} \over 2k_{B}T}\left({mv^{2} \over 2k_{B}T}-1\right)=0} eta, ondorioz, m...

{\text{e}}=\left({\frac {2}{1}}\right)^{1/1}\left({\frac {4}{1\cdot 3}}\right)^{1/2}\left({\frac {6\cdot 8}{5\cdot 7}}\right)^{1/4}\left({\frac {10\cdot...

\cot \left({\frac {\pi }{n}}\right)\cdot \ h} B = n 12 ⋅ l 2 ⋅ h ⋅ cot ⁡ ( π n ) {\displaystyle B={\frac {n}{12}}\cdot l^{2}\cdot h\cdot \cot \left({\frac...

{2\,\tan \left({{\pi } \over {n}}\right)}}} A = n l 2 4 tan ⁡ ( π n ) {\displaystyle A={{n\,l^{2}} \over {4\,\tan \left({{\pi } \over {n}}\right)}}} Definizioz...

\mathbb {R} :\quad u(x)=H(x)=\left\{{\begin{array}{rcl}0&\mathrm {baldin} &x<0\\1&\mathrm {baldin} &x\geq 0\end{array}}\right.} Funtzioa oso erabilia da...

Provo konpainiarekin iluntasunean ezkutatua A comrade on me left ai! another one on me right Adiskide bat nire ezkerrean ai! eta bestea eskuinean And a...

2008-08-11). Right and Left Hand Rules - Interactive Java Tutorial National High Magnetic Field Laboratory A demonstration of the right-hand rule at physics...

definitu zuen: E a = − R T ln ⁡ ( k A ) {\displaystyle E_{a}=-RT\ln \left({\frac {k}{A}}\right)} Ea aktibazio energia izanik, R gasen konstante unibertsala,...

{\displaystyle {\frac {V_{\mathrm {out} }}{V_{2}-V_{1}}}=\left(1+{2R_{1} \over R_{\mathrm {gain} }}\right){R_{3} \over R_{2}}} Anplifikadore operazional Datuak:...

{\displaystyle \delta _{ij}=\left\{{\begin{matrix}1&{\mbox{, }}i=j&{\mbox{bada}}\\0&{\mbox{, }}i\neq j&{\mbox{bada}}\end{matrix}}\right.} Izen hori du Leopold...

C_{c}=\lim _{A\to B}\left({\frac {Q}{\Delta T}}\right)_{c}=\sum _{i}q_{i}\left({\frac {dc_{i}}{dT}}\right)=\left({\frac {{\bar {d}}Q}{dT}}\right)_{c}} Non ( c...

\rho {\frac {Du}{Dt}}=\rho k-\nabla P+\mu \left({\frac {1}{3}}\nabla (\nabla \cdot u)+\nabla ^{2}u\right)} Datuak: Q201321 Multimedia: Navier-Stokes...

ix}}={\begin{pmatrix}f_{1}\left(x,\mathbf {y} ,\mathbf {y} ',\mathbf {y} '',\ldots ,\mathbf {y} ^{(n-1)}\right)\\f_{2}\left(x,\mathbf {y} ,\mathbf {y}...

0=\nabla _{\nu }\left(\xi ^{\mu }T_{\mu }^{\nu }\right)={\frac {1}{\sqrt {-g}}}\partial _{\nu }\left({\sqrt {-g}}\ \xi ^{\mu }T_{\mu }^{\nu }\right)} Integral...

∑ j = 0 k ( − 1 ) k − j ( k j ) j n . {\displaystyle S(n,k)=\left\{{n \atop k}\right\}={\frac {1}{k!}}\sum _{j=0}^{k}(-1)^{k-j}{k \choose j}j^{n}.}...

{1/n}{k}}={\frac {{\frac {1}{n}}\left({\frac {1}{n}}-1\right)\left({\frac {1}{n}}-2\right)\cdots \left({\frac {1}{n}}-k+1\right)}{k!}}} den ( 1 / n 0 ) = 1...

(cz_{k})\;{\overset {(2)}{\leq }}\;\sum _{k}|cz_{k}|=\sum _{k}\left|c\right|\left|z_{k}\right|=\sum _{k}\left|z_{k}\right|.} Froga honi esker, argi dago (*) berdintasuna...

{\displaystyle {\vec {\nabla }}n({\textbf {r}})-{d \over ds}\left[n({\textbf {r}}){{\textbf {dr}} \over {ds}}\right]=0} n errefrakzio-indizea, r posizio-bektorea eta...

2 N 1 ) {\displaystyle V_{o}=V_{S}\cdot \left({\frac {D}{1-D}}\right)\cdot \left({\frac {N_{2}}{N_{1}}}\right)} Irteerako iragazkia kapazitiboa da. Kontrola...

{\displaystyle \exists n,m\geq n_{0}} | a n − a m | < ϵ {\displaystyle \left\vert a_{n}-a_{m}\right\vert <\epsilon } (Barra bertikalak balio absolutua adierazten...

}={\frac {1}{\mu _{0}}}\left[F^{\mu \alpha }F^{\nu }{}_{\alpha }-{\frac {1}{4}}\eta ^{\mu \nu }F_{\alpha \beta }F^{\alpha \beta }\right]\,,} Tentsore honen...

{sin} \beta =2\ \operatorname {sin} \left({\frac {\alpha +\beta }{2}}\right)\cos \left({\frac {\alpha -\beta }{2}}\right)} sin ⁡ α − sin ⁡ β = 2   sin ⁡ (...

{\displaystyle f'=f\left({\frac {v}{v-v_{i}}}\right)} Kalkulua: f ′ = 500 H z ( 343 m / s 343 m / s − 30 m / s ) = 548 , 08 H z {\displaystyle f'=500Hz\left({\frac...

{\displaystyle {\frac {d}{dx}}\log _{b}(x)={\frac {d}{dx}}\left({\frac {1}{\ln(b)}}\ln {x}\right)={\frac {1}{\ln(b)}}{\frac {d}{dx}}\ln {x}={\frac {1}{x\ln(b)}}}...

2 ) 2 = ( a 1 a 2 ) 3 {\displaystyle \left({\frac {T_{1}}{T_{2}}}\right)^{2}=\left({\frac {a_{1}}{a_{2}}}\right)^{3}} Keplerrek, zuezkan datuekin, erlazioak...

{\displaystyle T\left(\theta \right)=T_{0}\left[1+\left({\frac {1}{2}}\right)^{2}\sin ^{2}{\frac {\theta }{2}}+\left({\frac {1\cdot 3}{2\cdot 4}}\right)^{2}\sin...

{F}_{\text{loop}}=\left(\mathbf {m} \times \nabla \right)\times \mathbf {B} =\nabla \left(\mathbf {m} \cdot \mathbf {B} \right)-\left(\nabla \cdot \mathbf {B} \right)\mathbf...

< x m i n . {\displaystyle F_{X}(x)={\begin{cases}1-\left({\frac {x_{\mathrm {min} }}{x}}\right)^{\alpha }&x\geq x_{\mathrm {min} },\\0&x<x_{\mathrm {min}...

{|E_{n}|}{|S_{n}|}}\leq \left[2\varepsilon +O(n\varepsilon ^{2})\right]{\frac {\sum \limits _{i=1}^{n}|x_{i}|}{\left|\sum \limits _{i=1}^{n}x_{i}\right|}}} ⇒ {\displaystyle...

n ⋅ tan ⁡ ( π n )   {\displaystyle A=a^{2}\cdot n\cdot \tan \left({\frac {\pi }{n}}\right)\ } A = n r 2 sin ⁡ ( 2 π n ) 2 {\displaystyle A={\frac {nr^{2}\sin({\frac...

{\displaystyle \alpha ={{{N} \over {N-1}}\left(1-{{\sum _{i=1}^{N}\sigma _{Y_{i}}^{2}} \over {\sigma _{X}^{2}}}\right)}} N {\displaystyle N} testeko item,...

g_{ij}}{\partial x^{c}}}\right)\left(2{\frac {\partial g_{bd}}{\partial x^{a}}}-{\frac {\partial g_{ab}}{\partial x^{d}}}\right)g^{ab}g^{cd}.\end{aligned}}}...

{s,m} }(T)&=ae^{\left(b-{\frac {T}{d}}\right)\left({\frac {T}{c+T}}\right)};\\[8pt]\gamma _{\mathrm {m} }(T,\mathrm {RH} )&=\ln \left({\frac {\mathrm {RH}...

\left\{{\begin{matrix}z_{0}&=&0\qquad \ &{\mbox{(hasierako terminoa)}}\qquad \\z_{n+1}&=&z_{n}^{2}+c&{\mbox{(indukzio-erlazioa)}}\end{matrix}}\right.}...

(Ingelesez) «Dutch election: GreenLeft and Animal Rights gains the bright spots as Wilders stalls and mainstream right strengthens | Links» links.org.au...

{\displaystyle [\rho ]=\left[{\frac {\text{masa}}{\text{bolumena}}}\right]=\left[{\frac {\text{M}}{{\text{L}}^{3}}}\right]={\text{M L}}^{-3},} [ v ]...

) a 2 ≈ 3 , 8855 a 2 {\displaystyle A=\left({\frac {\sqrt {25+10{\sqrt {5}}}}{4}}+5{\frac {\sqrt {3}}{4}}\right)a^{2}\approx 3,8855\,a^{2}} V = 5 + 5 24...

p 3 ) 1 / p {\displaystyle A\;\approx 4\pi \!\left({\frac {a^{p}b^{p}+a^{p}c^{p}+b^{p}c^{p}}{3}}\right)^{1/p}\,\!} Non p ≈ 1,6075. Adierazpen honekin...

A ∈ M n ( K ) {\displaystyle A\in {\mathcal {M}}_{n}\left(K\right)} matrize bat, non a i , j {\displaystyle a_{i,j}} bere elementuak diren...

\over \partial x^{\rho }}\right)={1 \over 2}g^{\lambda \rho }\left(g_{\rho \mu ,\nu }+g_{\rho \nu ,\mu }-g_{\mu \nu ,\rho }\right)} (komen eskuinean ageri...

{\displaystyle (A|b)=\left({\begin{matrix}a_{1,1}&\cdots &a_{1,n}\\\vdots &\ddots &\vdots \\a_{m,1}&\cdots &a_{m,n}\end{matrix}}\right|\left.{\begin{matrix}b_{1}\\\vdots...

bitartean. Beste hitz batzuetan, teoriak M ( u d ) {\displaystyle M\left({u \atop d}\right)} bezalako simetria transformazioak ditu, non u {\displaystyle u}...

zituena. Lau bertsio ezberdinetan eskaini zuten. LHD (Left Hand Drive) Euro Spec M5. RHD (Right Hand Drive) Spec M5. NA (Iparramerika) Spec edo 1988 M5...

} orduan y = f ( x 2 a ) ± 2 b   {\displaystyle y=f\left({\frac {x}{2a}}\right)\pm 2b\ } kurbaren bi adarrak dira jatorrian. Datuak: Q3822077...

page-width="21cm" margin-top="5mm" margin-bottom="10mm" margin-left="20mm" margin-right="20mm"> <fo:region-body margin-top="10mm" margin-bottom="10mm"...

NL V FL − 1 ) R L {\displaystyle R_{\text{int}}=\left({{\frac {V_{\text{NL}}}{V_{\text{FL}}}}-1}\right){R_{\text{L}}}} Théveninen teorema Nortonen teorema...

_{i=1}^{n}(x_{i}-{\overline {x}})^{4}}{\left({\tfrac {1}{n}}\sum _{i=1}^{n}(x_{i}-{\overline {x}})^{2}\right)^{2}}}\ } , non m k {\displaystyle m_{k}\...

p q ≤ t ) = Φ ( t ) {\displaystyle \lim _{n\to \infty }\operatorname {P} \left({\frac {X_{n}-np}{\sqrt {npq}}}\leq t\right)=\Phi (t)} Datuak: Q1855610...

2 2 ⋅ g ) {\displaystyle V_{t}={\sqrt {2\cdot g\cdot \left(h+{\frac {v_{0}^{2}}{2\cdot g}}\right)}}} formularen bidez adierazten da.   V t {\displaystyle...

) {\displaystyle \left({\begin{array}{ccc|ccc}2&1&-1&1&0&0\\-3&-1&2&0&1&0\\-2&1&2&0&0&1\end{array}}\right)\rightarrow (L_{1}/2)\left...

{\begin{aligned}f(x)&=ax^{2}+bx+c\\&=a(x-h)^{2}+k\\&=a\left(x-{\frac {-b}{2a}}\right)^{2}+\left(c-{\frac {b^{2}}{4a}}\right),\\\end{aligned}}} eta orduan, forma estandarreko...

= 0 {\displaystyle \left.{\begin{matrix}2x&+&y&+&z&=&0\\&&3y&+&2z&=&0\\&&&&4z&=&0\end{matrix}}\right\}\Longleftrightarrow \left\{{\begin{matrix}x=0\...

k_{1}=f\left(t_{i},y_{i}\right)} k 2 = f ( t i + 1 2 h , y i + 1 2 k 1 h ) {\displaystyle k_{2}=f\left(t_{i}+{1 \over 2}h,y_{i}+{1 \over 2}k_{1}h\right)} k...

y + z ) 2 = 16 x 2 25 y 2 + 8 x z 5 y + z 2 {\displaystyle \left({\frac {4x}{5y}}+z\right)^{2}={\frac {16x^{2}}{25y^{2}}}+{\frac {8xz}{5y}}+z^{2}} ( 8...

{\displaystyle \left\{{\begin{matrix}x(\theta )=a\cos \theta (1+\cos \theta )\\y(\theta )=a\sin \theta (1+\cos \theta )\end{matrix}}\right.} non a bi zirkunferentzietako...

-{\frac {1}{c^{2}}}{\frac {\partial ^{2}}{\partial t^{2}}}\psi =\left({\frac {mc}{\hbar }}\right)^{2}\psi .} Diracen ekuazioan agertzen da (Einsteinen batuketa-konbentzioak...

4 π R 2 σ ) 1 / 4 {\displaystyle T_{\mathrm {eff} }=\left({\frac {L}{4\pi R^{2}\sigma }}\right)^{1/4}} non L {\displaystyle L} izarraren argitasua den...

{\displaystyle \left\vert xy\right\vert =\left\vert x\right\vert \left\vert y\right\vert } | x y | = | x | | y | {\displaystyle \left\vert {\frac {x}{y}}\right\vert...

q ) Γ ( q ) = − ψ ( q ) {\displaystyle \lim _{s\to 1}\left[\zeta (s,q)-{\frac {1}{s-1}}\right]={\frac {-\Gamma '(q)}{\Gamma (q)}}=-\psi (q)} non Γ baita...

e 2 4 π ϵ 0 h c ) {\displaystyle g_{e}=2(1+a)=2\left(1+{\frac {q_{e}^{2}}{4\pi \epsilon _{0}hc}}\right)} Non: q e {\displaystyle q_{e}\;} elektroiaren...

(2n+1)}}={\frac {2}{\sqrt {\pi }}}\left(z-{\frac {z^{3}}{3}}+{\frac {z^{5}}{10}}-{\frac {z^{7}}{42}}+{\frac {z^{9}}{216}}-\ \cdots \right)} Besteak beste, errore...

I'd gladly give The red drops of my heart." And when we left our cabins, boys, We left with right good will To see our friends and neighbours That were...

= ∭ V ( ∇ ⋅ v ) d V . {\displaystyle \iint _{S}\mathbf {v} \cdot d\mathbf {S} =\iiint _{V}\left(\nabla \cdot \mathbf {v} \right)dV.} Datuak: Q8737769...

x {\displaystyle I=\int f\left(x,u,{\frac {\partial u}{\partial x}},{\frac {\partial ^{2}u}{\partial x^{2}}},\ldots \right)\,dx} , eta integral horren...

ds^{2}=-c^{2}\left(1-{\frac {2GM}{c^{2}r}}\right)\mathrm {d} t^{2}+\left(1-{\frac {2GM}{c^{2}r}}\right)^{-1}\mathrm {d} r^{2}+r^{2}\left(\mathrm {d} \theta...

{\nabla }}\Phi =\left({\frac {\partial \Phi }{\partial x}},{\frac {\partial \Phi }{\partial y}},{\frac {\partial \Phi }{\partial z}}\right)} Kasu horretan...

{\displaystyle {1 \over \rho }{\partial \over \partial \rho }\left(\rho {\partial u \over \partial \rho }\right)+{1 \over \rho ^{2}}{\partial ^{2}u \over \partial...

_{B}^{}\geq \left|{\frac {1}{2i}}\langle [{\hat {A}},{\hat {B}}]\rangle \right|={\frac {1}{2}}\left|\langle [{\hat {A}},{\hat {B}}]\rangle \right|} Ziurgabetasunak...

{C}}+BCD}}\\&=\left({\overline {{\overline {A}}\,{\overline {B}}}}\right)\left({\overline {{\overline {A}}\,{\overline {C}}}}\right)\left({\overline {BCD}}\right...

{\displaystyle {\frac {d^{2}}{dx^{2}}}\Psi (x)={\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)\Psi (x)\equiv {\frac {2m}{\hbar ^{2}}}M(x)\Psi (x),} Erabilitako...

ekuazioa: A = ( 1329 × 10 − H / 5 D ) 2 {\displaystyle A=\left({\frac {1329\times 10^{-H/5}}{D}}\right)^{2}} Bertan, albdeo geometrikoa A {\displaystyle A}...

d 2 − a 2 − c 2 ) tan ⁡ θ {\displaystyle A={\frac {1}{4}}\left(b^{2}+d^{2}-a^{2}-c^{2}\right)\tan \theta } A = 1 4 4 e 2 f 2 − ( b 2 + d 2 − a 2 − c 2...

{\displaystyle \varphi (n)=n\prod _{p\mid n}\displaystyle {\Biggl (}1-\left({\frac {1}{p}}\right){\Biggr )}} idazten da, non p dira lehen desberdinak n zatitzen...

_{x\to \infty }\left(1+{\frac {1}{x}}\right)^{x}}=\,e}     (e zenbakia) lim x → 0 ( s e n ⁡ x x ) = 1 {\displaystyle {\lim _{x\to 0}\left({\frac {\operatorname...

A {\displaystyle \nabla \times \left(\nabla \times \mathbf {A} \right)=\nabla \left(\nabla \cdot \mathbf {A} \right)-\nabla ^{2}\mathbf {A} } Non A {\displaystyle...

{\displaystyle x={\frac {\left|{\begin{array}{cc}e&b\\f&d\end{array}}\right|}{\left|{\begin{array}{cc}a&b\\c&d\end{array}}\right|}}={\frac {ed-bf}{ad-bc}}}...

lortzen da: | 1 π − a n | <= 16 ( 4 n ) ( e − 2 π 4 n ) {\displaystyle \left|{\frac {1}{\pi }}-a_{n}\right|<=16\;(4^{n})(e^{-2\pi 4^{n}})} Datuak: Q3751018...

{\mathcal {Y}}}\sum _{x\in {\mathcal {X}}}{p(x,y)\log {\left({\frac {p(x,y)}{p(x)\,p(y)}}\right)}},} non p ( x , y ) {\displaystyle p(x,y)} X {\displaystyle...

_{2}'\ldots \nu _{l}'}={\left(R^{-1}\right)}{}^{\mu _{1}'}{}_{\mu _{1}}{\left(R^{-1}\right)}{}^{\mu _{2}'}{}_{\mu _{2}}\ldots {\left(R^{-1}\right)}{}^{\mu _{n}'}{}_{\mu...

a n t e a P = K o n s t a n t e a } ⟶ V 1 n 1 = V 2 n 2 {\displaystyle \left.{\begin{array}{l}{\cfrac {P_{1}\cdot V_{1}}{T_{1}\cdot n_{1}}}={\cfrac {P_{2}\cdot...

p {\displaystyle \beta ^{*}=-{\frac {1}{\rho }}\left({\frac {\partial \rho }{\partial C_{a}}}\right)_{T,p}} eta g grabitatearen azelerazioa den. Ca,...

p . {\displaystyle M_{p}(x_{1},\dots ,x_{n})=\left({\frac {1}{n}}\cdot \sum _{i=1}^{n}x_{i}^{p}\right)^{1/p}.} p < q {\displaystyle p<q} betetzen bada...

2 ( t ) x ′ ( t ) d t | {\displaystyle V=\pi \left|\int \limits _{t_{1}}^{t_{2}}y^{2}(t)x'(t)\,dt\right|} Azalera: S = 2 π ∫ t 1 t 2 | y ( t ) | [ x ′...

0 , 5 ) 2 b + c {\displaystyle {\hat {\mathrm {X} }}^{2}={\frac {(\left|b-c\right|-0,5)^{2}}{b+c}}} 0.5eko faktorea jarraitasun zuzenketa egiteko sartzen...

ext{in}}^{+}-V_{\text{in}}^{-})+A_{\text{c}}\left({\frac {V_{\text{in}}^{+}+V_{\text{in}}^{-}}{2}}\right)} Ekuazio honetan ageri den Ac terminoari, modu...

Became the Loudest Voice on the Far Right» NBC News. ↑ McKay, Tom. (April 28, 2018). «Jack Dorsey Apologizes to Far-Right Activist Candace Owens After a Twitter...

eskubikoari R (ingelesez right esaten delako) hizkia gehitzen zaiolarik (adibidez 03R edo R03) eta ezkerrekoari L (ingelesez left esaten delako) hizkia gehitzen...

x^{(\lambda )}=\left\{{\begin{matrix}{\frac {(x+m)^{\lambda }-1}{\lambda }}&\lambda \neq 0&x>-m\\ln(x+m)&\lambda =0&m>0\end{matrix}}\right.} non λ {\displaystyle...

{\displaystyle \left({\frac {d^{2}x^{\lambda }}{d\sigma ^{2}}}\right)_{P}=0} ( d 2 x ¯ λ d σ 2 + Γ μ ν λ d x ¯ μ d σ d x ¯ ν d σ ) Q = 0 {\displaystyle \left({\frac...

{\displaystyle \left\{{\begin{array}{lr}\displaystyle \left({\frac {x-h}{a}}-{\frac {y-k}{b}}\right)\left({\frac {x-h}{a}}+{\frac {y-k}{b}}\right)=0\\\\\displaystyle...

O(g(x))=\left\{{\begin{matrix}f(x):{\mbox{existitzen da }}x_{0},c>0{\mbox{ non}}\\\forall x\geq x_{0}>0:0\leq |f(x)|\leq c|g(x)|\end{matrix}}\right\}} f(x)...

\mathbb {N} ^{*}.} Ondorioz, n + 1 | ( 2 n n ) {\displaystyle n+1|\left({\frac {2n}{n}}\right)} Catalan zenbakien errepikapen erlazioa: { C 0 = 1 C n = C o...

{\displaystyle \pi (x)={\rm {Li}}(x)+O\left(x\,\exp \left(-{\frac {A(\ln x)^{3/5}}{(\ln \ln x)^{1/5}}}\right)\right)} non O ( f ( x ) ) {\displaystyle O(f(x))}...

(2016ko ekainak 12). «Napoleonek dioen aldetik gidatu» Argia CC-BY-SA lizentzia. Datuak: Q220656 Multimedia: Right- and left-hand traffic / Q220656...

Ludwig von Mises eta Ayn Rand harreman estua izan ostean, 1965 urtean Left and Right aldizkaria sortu zuen, sistemaren aurkako bi joeren konbergentzia proposatzen...

=\sum _{j=1}^{n}\left[{\frac {\partial }{\partial x_{j}}}\right]{\boldsymbol {\hat {e}}}_{j}=\left[{\frac {\partial }{\partial x_{1}}}\right]{\boldsymbol...

{\displaystyle \left\vert {{\vec {a}}\cdot {\vec {b}}}\right\vert =\left\vert {\vec {a}}\right\vert \cdot \left\vert {\vec {b}}\right\vert \cdot \cos...

{A_{c}}{H^{2}}}={\frac {{\frac {\sqrt {3}}{4}}\cdot a^{2}}{\left({\frac {\sqrt {6}}{3}}\cdot a\right)^{2}}}={\frac {3{\sqrt {3}}}{8}}sr\approx 0,650sr} Datuak:...

existitzen dira: | Q / 2 π ε 0 G | << M {\displaystyle \left\vert Q/2{\sqrt {\pi \varepsilon _{0}G}}\right\vert <<M} : Schwarzschilden zulo beltzaren oso antzekoa...

+ C − ( H + X − N 2 ) {\displaystyle {\displaystyle AM=1+C-\left({\dfrac {H+X-N}{2}}\right)}} non C = karbono-atomoen kopurua, H = hidrogeno-atomoen kopurua...

Y | ∃ x ∈ X , f ( x ) = y } {\displaystyle Im_{f}:=\left\{y\in Y\;|\;\exists x\in X,\;f(x)=y\right\}} Irudi-multzoa kodominioaren azpimultzo bat da, beste...

cos ⁡ θ ) , {\displaystyle \Delta \lambda ={\frac {h}{m_{e}c}}\left(1-\cos \theta \right),} non h Plancken konstantea den, me elektroiaren masa, c argiaren...

Own Way (1967) My Songs (1967) Luke The Drifter Jr. (1968) Songs My Father Left Me (1969) Luke the Drifter Jr. Vol. 2 (1969) Live at Cobo Hall (1969) Sunday...

{\mathcal {F}}\{f(at)\}(\omega )={\frac {1}{|a|}}\,{\hat {f}}\!\left({\frac {\omega }{a}}\right)} Konboluzioaren teorema: Bi funtzioren, f {\displaystyle {f}}...

{\displaystyle \ln(x)=2\sum _{n=0}^{\infty }{\frac {1}{2n+1}}\left({\frac {x-1}{x+1}}\right)^{2n+1}} sin ⁡ x = ∑ n = 0 ∞ ( − 1 ) n ( 2 n + 1 ) ! x 2 n +...

(1939) A Place of One's Own (eleberria) (1940) Selected Poems (1943) Left Hand! Right Hand! (autobiografia, 1. lib.) (1944) Sing High, Sing Low (saiakerak)...

= sin ⁡ ( π 2 + θ ) . {\displaystyle \cos(\theta )=\sin \left({\frac {\pi }{2}}+\theta \right).} Kosinuaren erreziprokoa sekantea da, esaterako, cos ⁡...

{\displaystyle t=\gamma \left(t'+{\frac {v}{c^{2}}}x'\right)} x = γ ( x ′ + v t ′ ) {\displaystyle x=\gamma \left(x'+vt'\right)} y = y ′ {\displaystyle...

}\left({\sqrt {g}}\right)\equiv \left({\sqrt {g}}\right)_{;\mu }=0,} non g = | det ( g μ ν ) | . {\displaystyle g=\left|\det \left(g_{\mu \nu }\right)\right|...

{c}{g}}\ln \left({\frac {gt}{c}}+{\sqrt {1+\left({\frac {gt}{c}}\right)^{2}}}\right)={\frac {c}{g}}\operatorname {arsinh} \left({\frac {gt}{c}}\right)} Ontziaren...

3 ∪ … . {\displaystyle V^{*}=\bigcup _{i\in \mathbb {N} }V_{i}=\left\{\lambda \right\}\cup V_{1}\cup V_{2}\cup V_{3}\cup \ldots .} Hau da, V {\displaystyle...

{\displaystyle \left\|\mathbf {a} \times \mathbf {b} \right\|=\left\|\mathbf {a} \right\|\left\|\mathbf {b} \right\|\left|\sin \theta \right|} ; biderketa...

{\left\langle 0\left|T\left\{\phi _{I}(x)\phi _{I}(y)\exp \left[-i\int _{-T}^{T}dt\,H_{I}(t)\right]\right\}\right|0\right\rangle }{\left\langle 0\left|T\left\{\exp...

{\displaystyle {\frac {1}{f'}}={\frac {1}{F}}-{\frac {1}{f}}=\left({\frac {1}{18}}-{\frac {1}{17}}\right)\cdot 10^{3}{\text{ m}}^{-1}=-3.3{\text{ dioptriak}}}...

− 3 e 3 ) ] k B T ≈ 2.821   k B T {\displaystyle E=\left[3+W\left({\frac {-3}{e^{3}}}\right)\right]k_{\mathrm {B} }T\approx 2.821\ k_{\mathrm {B} }T} non...

Modern Social Order. Cambridge : Polity. Giddens, Anthony (1994) Beyond Left and Right — the Future of Radical Politics. Cambridge : Polity. Giddens, Anthony...

r 2 + r 2 d σ 2 {\displaystyle ds^{2}=-\left(1-{\dfrac {2m}{r}}\right)dt^{2}+\left(1-{\dfrac {2m}{r}}\right)^{-1}dr^{2}+r^{2}d\sigma ^{2}} Non d σ 2...

A ‖ = | c | ⋅ ‖ A ‖ , ∀ c ∈ R . {\displaystyle \lVert cA\rVert =\left\vert c\right\vert \cdot \lVert A\rVert ,\forall c\in {\displaystyle \mathbb {R}...

\forall n\geq n_{0}} | a n n − l | < 1 − l 2 {\displaystyle \left\vert {\sqrt[{n}]{a_{n}}}-l\right\vert <{\frac {1-l}{2}}} Bi aldeetan l {\displaystyle l}...

) = I ∘ Z 1 Z 2 Z 1 + Z 2 {\displaystyle V_{2}=I_{\circ }\left(Z_{1}\parallel Z_{2}\right)=I_{\circ }\textstyle {Z_{1}Z_{2} \over Z_{1}+Z_{2}}} Bilatzen...

}-{\frac {2}{D-2}}\Lambda g_{\mu \nu }=\kappa \left(T_{\mu \nu }-{\frac {1}{D-2}}Tg_{\mu \nu }\right)}} D=4 dimentsiok hau horrela murrizten dute: R...

{\displaystyle \theta =\arcsin \left({\frac {\text{aurkakoa}}{\text{hipotenusa}}}\right)=\sin ^{-1}\left({\frac {a}{h}}\right).} k zenbaki oso baterako, sin...

F_{x}=q\left(E_{x}+v_{y}B_{z}-v_{z}B_{y}\right),} F y = q ( E y + v z B x − v x B z ) , {\displaystyle F_{y}=q\left(E_{y}+v_{z}B_{x}-v_{x}B_{z}\right),} F...

\left(x_{1}-vt_{1}\right)&\quad \mathrm {eta} \quad &&x_{2}^{'}&=\gamma \left(x_{2}-vt_{2}\right)\\t_{1}^{'}&=\gamma \left(t_{1}-vx_{1}/c^{2}\right)&\quad...

(g_{1}g_{2})}}=v_{i^{\left(\tau (g_{1})\ \circ \ \tau (g_{2})\right)}}\\&=\ v_{\left(i^{\tau (g_{1})}\right)^{\tau (g_{2})}}=\left(v_{i^{\tau (g_{1})}}\right)R_{\tau...

betetzen dute. | ( u , v ) | 2 ≤ ( u , u ) ( v , v ) {\displaystyle \left\vert (u,v)\right\vert ^{2}\leq (u,u)(v,v)} Non ( ⋅ , ⋅ ) {\displaystyle (\cdot ,\cdot...

≈ 2 π n ( n e ) n {\displaystyle n!\approx {\sqrt {2\pi n}}\left({\frac {n}{e}}\right)^{n}} (Stirlingen Formula) ζ ( 2 ) = 1 1 2 + 1 2 2 + 1 3 2 + 1...

x + d = ( a b d ) ( b c ) x . {\displaystyle ab^{cx+d}=\left(ab^{d}\right)\left(b^{c}\right)^{x}.} Aldagai erreal baten funtzio gisa, funtzio esponentzialen...

){df(t) \over dt}=f(t)\left\{-{\frac {\hbar ^{2}}{2m}}\nabla ^{2}\psi (\mathbf {r} )+V(\mathbf {r} )\psi (\mathbf {r} )\right\}} hau da i ℏ 1 f ( t )...

. ) {\displaystyle \left({\frac {1}{1}},-{\frac {1}{3}},{\frac {1}{5}},-{\frac {1}{7}},{\frac {1}{9}},-{\frac {1}{11}},...\right)} . Leibnizen serie bezala...

2 ) 2 {\displaystyle R_{1}={\frac {2L}{\sqrt {1-\left({\frac {\frac {vt}{2}}{\frac {ct}{2}}}\right)^{2}}}}} Azkenik, 1 bidaia sinplifikatu ondoren lortzen...

{\displaystyle I_{D}=\mu _{n}C_{ox}{\frac {W}{L}}\left((V_{GS}-V_{th})V_{DS}-{\frac {V_{DS}^{2}}{2}}\right)} Kasu hau honako baldintzekin ematen da: VGS >...

table. Brady with his wife Juliet Handy Brady (front left) and sister Ellen Brady Haggerty (front right). General William J. Worth; a related picture also...

2023-01-18). ↑ Klatch, Rebecca E.. (1999). A generation divided : the new left, the new right, and the 1960s. Berkeley : University of California Press ISBN 978-0-520-21714-0...

{\displaystyle {\text{d}}V=\left({\frac {\partial V}{\partial P}}\right)_{\theta }{\text{d}}P+\left({\frac {\partial V}{\partial \theta }}\right)_{P}{\text{d}}\theta...

d a = − ( Δ r G ∘ V e F ) {\displaystyle Ezelda=-\left({\frac {\Delta _{r}G^{\circ }}{VeF}}\right)} Hala ere, pila baten potentzial elektriko estandarra...

_{10}\left({\frac {I}{I_{iso}}}\right)} G d B d = 10 log 10 ⁡ ( I I d i p o l o ) {\displaystyle G_{dBd}=10\log _{10}\left({\frac {I}{I_{dipolo}}}\right)}...

+ sin 2 ⁡ θ d ϕ 2 ) {\displaystyle g_{\Omega }=\left(d\theta ^{2}+\sin ^{2}\theta \,d\phi ^{2}\right)} ): Schwarzschilden soluzioaren espazio-kurbatura...

papera lortu zuen Lal Joseren 2012ko Diamond Necklace filmean. Ondoren, Left Right Left (2013), Pullipulikalum Aattinkuttiyum (2013) eta Angry Babies in Love...

{0} }\left({\frac {1}{n_{i}^{2}}}-{\frac {1}{n_{f}^{2}}}\right)\ =-E_{\mathrm {0} }\left({\frac {1}{n_{f}^{2}}}-{\frac {1}{n_{i}^{2}}}\right)\ ={m_{\mathrm...

{\displaystyle g_{tt}=-\left(1-{\frac {2Mr}{\Sigma }}\right)={\frac {1}{\Sigma }}\left(r^{2}-2Mr+a^{2}\cos ^{2}\theta \right)={\frac {1}{\Sigma...

{\displaystyle {\dfrac {dx^{i}}{dt}}=0\Rightarrow dt=c\left(-g_{00}\left[{\dfrac {d(ct)}{dt}}\right]^{2}\right)^{-1/2}d\tau } Fotoia geodesika nulu batean barrena...

"Into the Blue". "Aeroplanes". "Spider and the Fly". "It's What's Left, That Makes It Right". "Smash the Glass". "Salutations". "A Captain Needs a Ship"....

| ( x ′ 2 + y ′ 2 ) 3 / 2 {\displaystyle \kappa (s)={\frac {\left\vert x'y''-y'x''\right\vert }{(x'^{2}+y'^{2})^{3/2}}}} Koordenatu gabeko era batean...

lortuko da,  {\displaystyle y=y_{a}+\left(y_{b}-y_{a}\right){\frac {x-x_{a}}{x_{b}-x_{a}}}{\text{ horrela, }}\left(x,y\right){\text{ puntua lortuko da, }}}...

\left|P_{n}-P_{n-1}\right|<\varepsilon } Zehaztasun erlatiboa: | P n − P n − 1 P n | < ε {\displaystyle \left|{\frac {P_{n}-P_{n-1}}{P_{n}}}\right|<\varepsilon...

Δ C P ∘ d T {\displaystyle \Delta H^{\circ }\!\left(T\right)=\Delta H^{\circ }\!\left(T^{\circ }\right)+\int _{T^{\circ }}^{T}\Delta C_{P}^{\circ }\,\mathrm...

{1}{r\sin \theta }}\left({\frac {\partial (\sin \theta F_{\theta })}{\partial \theta }}+{\frac {\partial F_{\varphi }}{\partial \varphi }}\right)} Dibergentziaren...

λ ) , {\displaystyle \psi (\theta )=\mathrm {sinc} \left({\frac {\pi a\theta }{\lambda }}\right),} eta zeroak ditu θ = ± n λ / a {\displaystyle \theta...

{\displaystyle ds^{2}=-\left(1-{\frac {r_{s}r}{\Sigma }}\right)c^{2}dt^{2}+{\frac {\Sigma }{\Delta }}dr^{2}+\Sigma d\theta ^{2}+\left(r^{2}+a^{2}+{\frac...

{2}}=-\left({\frac {GM}{c^{2}r^{3}}}\right)c^{2}\xi ^{\hat {2}}=-{\frac {GM}{r^{3}}}\xi ^{\hat {2}},\;a^{\hat {3}}=-\left({\frac {GM}{c^{2}r^{3}}}\right)c^{2}\xi...

Marans, Z; Griffiths, S; Hsu, D. (2004-2-11). «Scimitar vein draining to the left atrium and a historical review of the scimitar syndrome» Pediatric radiology...

S={\frac {1}{2}}{\sqrt {\left(\det {\begin{pmatrix}x_{A}&x_{B}&x_{C}\\y_{A}&y_{B}&y_{C}\\1&1&1\end{pmatrix}}\right)^{2}+\left(\det...

DISORDERS OF THE BODY IMAGE. The Journal of Nervous and Mental Disease, 1958 Right-Left Discrimination and Finger Localization. The Journal of Nervous and Mental...

_{i=1}^{N}\left|{\frac {\partial f}{\partial x_{i}}}\right|\varepsilon _{\rm {a}}(x_{i})=\left|{\frac {\partial f}{\partial x_{1}}}\right|\varepsilon...

E=m_{0}c^{2}\left[1+{\frac {1}{2}}\left({\frac {v}{c}}\right)^{2}+{\frac {3}{8}}\left({\frac {v}{c}}\right)^{4}+{\frac {5}{16}}\left({\frac {v}{c}}\right)^{6}+\ldots...

c d ( n , m ) {\displaystyle {\mathrm {mcd} }\left(f_{n},f_{m}\right)=f_{{\mathrm {mcd} }\left(n,m\right)}} . Izan bedi f p = a {\displaystyle f_{p}=a}...

{\displaystyle kp={\frac {\left(P_{T}\cdot X_{C}\right)^{c}}{\left(P_{T}\cdot X_{A}\right)^{a}\cdot \left(P_{T}\cdot X_{B}\right)^{b}}}} ⟹ {\displaystyle...

Zeina honela kalkulatzen den: a = ( o h 2 ) {\displaystyle a=\left({\frac {oh}{2}}\right)} Zeinetan a {\displaystyle a} azalera den, o {\displaystyle o}...

\operatorname {z.k.h.} (a,b)=\operatorname {z.k.h.} (b,a-b\left\lfloor {a \over b}\right\rfloor ).}   zkh ⁡ ( a , b ) = d {\displaystyle \ \operatorname...

_{i=1}^{n}(x_{i}-{\overline {x}})^{3}}{\left({\tfrac {1}{n}}\sum _{i=1}^{n}(x_{i}-{\overline {x}})^{2}\right)^{3/2}}},\!} non m 3 , m 2 {\displaystyle...

x − v t ) ) , {\displaystyle y(x,t)=A\cos {\Bigl (}2\pi \left({\frac {x}{\lambda }}-ft\right){\Bigr )}=A\cos {\Bigl (}{\frac {2\pi }{\lambda }}{\bigl...

{\displaystyle \left\{{\begin{matrix}(I)&x-2y-3z+4t=0\\(II)&3x+y+5z+5t=0\\(III)&-2x+3y+4z-7t=0\end{matrix}}\right.\Leftrightarrow \left...

{1}{\sqrt {4\pi \lambda k_{b}T}}}\exp \left(-{\frac {(\lambda +\Delta G^{\circ })^{2}}{4\lambda k_{b}T}}\right)} ↑ Closs, G.L.; Calcaterra, L.T.; Green...

eta interpretatzen du. Apologies (2017) The Nationality (2014) From right to left (2017) How must I believe (2013) Paranoia Fairouz Small Manifesto Farah...

the man on sight. So they sent for reinforcements through the county left and right. Three thousand men surrounded him, they hunted near and far. But he...

jarraituz: | a n + 1 a n − l | < 1 − l 2 {\displaystyle \left\vert {{a_{n+1} \over a_{n}}-l}\right\vert <{1-l \over 2}} Ezkerretan daukagun " − l {\displaystyle...

] ⟶ 1 J = 1 kg m 2 s − 2 . {\displaystyle [E_{\text{k}}]=\left[{\frac {1}{2}}mv^{2}\right]\longrightarrow {\text{1 J}}={\text{1 kg m}}^{2}{\text{s}}^{-2}...

warnings it's anti-Semitic» Newsweek. ↑ Stack, Liam. (2017-08-15). «Alt-Right, Alt-Left, Antifa: A Glossary of Extremist Language» The New York Times ISSN...

0}{\frac {1}{h}}\left(Y_{x_{0}}-\tau _{x_{h}}^{-1}\left(Y_{x_{h}}\right)\right)=\left.{\frac {d}{dt}}\left(\tau _{x_{t}}Y\right)\right|_{t=0}} Suposa dezagun...

| {\displaystyle |x|\leq \left|{\frac {b}{d}}\right|} eta | y | ≤ | a d | {\displaystyle |y|\leq \left|{\frac {a}{d}}\right|} a {\displaystyle a} eta...

{\displaystyle v=\max \,} h i = ⌊ t 60 ⌋ mod 6 {\displaystyle h_{i}=\left\lfloor {\frac {t}{60}}\right\rfloor \mod 6} f = t 60 − h i {\displaystyle f={\frac {t}{60}}-h_{i}}...

t^{2}+a(t)^{2}\left({\frac {\operatorname {d} \!r^{2}}{1-kr^{2}}}+r^{2}\operatorname {d} \!\theta ^{2}+r^{2}\sin ^{2}\theta \operatorname {d} \!\varphi ^{2}\right)}...

I D S S ( 1 − V G S V P ) 2 {\displaystyle I_{D}=I_{DSS}\left(1-{\frac {V_{GS}}{V_{P}}}\right)^{2}} Kurba horretan dauden puntuak asetazun zonan dagoen...

h ( q − 1 ) m {\displaystyle m^{ed}=m^{(ed-1)}m=m^{h(p-1)(q-1)}m=\left(m^{p-1}\right)^{h(q-1)}m} Fermaten teorema txikia erabiliz, m p − 1 ( mod p ) ≡...

0 {\displaystyle \mathrm {idf} ({\mathsf {''this''}},D)=\log \left({\frac {2}{2}}\right)=0} Beraz, TDIDFa zero da "this" hitzarentzat, eta horrek hitza...

^{2}={}&\left(1-{\frac {r_{s}r}{\rho ^{2}}}\right)c^{2}dt^{2}-{\frac {\rho ^{2}}{\Delta }}dr^{2}-\rho ^{2}d\theta ^{2}\\&-\left(r^{2}+\alpha ^{2}+{\frac...

du: ( 1 + 1 n ) n → e ,     n → ∞     doalarik {\displaystyle \left(1+{\frac {1}{n}}\right)^{n}\rightarrow e,\ \ n\rightarrow \infty \ \ {\text{doalarik}}}...

left({\frac {V_{i}}{V_{f}}}\right)^{(\gamma -1)}} → P f P i = ( V i V f ) γ {\displaystyle {\frac {P_{f}}{P_{i}}}=\left({\frac {V_{i}}{V_{f}}}\right)^{\gamma...

advocates seek public apology, reparations» Masslive. ↑ (Ingelesez) Carey, Matt. (2009). «Ari Ne’eman on disability» Left Brain Right Brain. Datuak: Q653856...

that "Edward Lear" was merely a pseudonym. Lear (on the right) is showing the stranger (left) the inside of his hat, with his name in the lining. Illustration...

}}=2\pi hc^{2}\left({\frac {hc}{kT\lambda ^{7}}}{\frac {e^{\frac {hc}{\lambda k_{B}T}}}{\left(e^{\frac {hc}{\lambda k_{B}T}}-1\right)^{2}}}-{\frac {1}{\lambda...

parliament sees birth of new right-wing group» EUobserver 2009-6-22 (kontsulta data: 2011-7-18). (Ingelesez) «Tory minders gag right-wing allies in the ECR»...

1964an ere Catherine Hall historialariarekin ezkondu zen. Era berean, New Left Review aldizkaria sortu zutenetako bat izan zen eta Raymond Williams, Richard...

β ) . {\displaystyle H(s)=\left({\frac {1}{\beta -\alpha }}\right)\cdot \left({1 \over s+\alpha }-{1 \over s+\beta }\right).} Azkenik, linealtasunaren...

Z^{+}\cdot Z^{-}\cdot q^{2}}{4\pi \varepsilon _{0}\cdot d_{0}}}\cdot \left(1-{\frac {1}{n}}\right)} Non N a {\displaystyle N_{a}} Avogadroren zenbakia den, A {\displaystyle...

{\displaystyle 12a^{3}b^{2}-30a^{4}bc+18a^{2}b^{3}c^{2}=6a^{2}b\left(2ab-5a^{2}c+3b^{2}c^{2}\right).} ↑ Mendelson, Elliott. (2015). Introduction to mathematical...

{\displaystyle 1{\text{kg}}={\frac {\left(299792458\right)^{2}}{\left(6.62607015\times 10^{-34}\right)\left(9192631770\right)}}{\frac {h\,\Delta \nu _{Cs}}{c^{2}}}\approx...

Books, 2003), ISBN 978-1-85984-689-6 Arguments for a New Left: Answering the Free-market Right (Blackwell, 1994), ISBN 978-0-631-19191-9 Labour: A Tale...

edo yrako. Hala ere, f ( 1 n , 1 n ) {\displaystyle f\left({\tfrac {1}{n}},{\tfrac {1}{n}}\right)} sekuentziak, n {\displaystyle n} arruntentzat, lim n...

ere erakusten du, ordea: "One Piece At A Time", "The One On The Right Is On The Left", "A Boy Named Sue", eta beste gai ugari era bai. Hala ere, arrakasta...

for antisemitic Facebook post attacking Green Party leader Zack Polanski» Left Foot Forward. ↑ Polanski, Zack. Green Party leader Zack Polanski speech to...

zen Ezkertien Erakunde Internazionala da. Beren eguna abuztueren 13an da. Left Hand (West Virginia, EEUU) bizilagun guztiak ezkertiak dira. Hala ere, gure...

− Γ t {\displaystyle \left[{S}_{1}\right]=\left[{S}_{1}\right]_{0}e^{-\Gamma t}} non [ S 1 ] {\displaystyle \left[{S}_{1}\right]} t {\displaystyle t}...

\int _{0}^{x}{\frac {dt}{1+t}}=\int _{0}^{x}\left(1-t+t^{2}-\cdots +(-t)^{n-1}+{\frac {(-t)^{n}}{1+t}}\right)\,dt} eta gaiz gai integratuz, ln ⁡ ( 1 + x...

{\displaystyle {\begin{aligned}\operatorname {Re} \left\{{\frac {d}{dt}}(Ae^{i\theta }\cdot e^{i\omega t})\right\}=\operatorname {Re} \{Ae^{i\theta }\cdot i\omega...

25ean, XG-k ingelesezko hirugarren singlea kaleratu zuen, "Shooting Star""Left Right" abesti gehigarriarekin batera. Chisa (チサ) 20 Hinata (ヒナタ) 20 Jurin (ジュリン)...

(1998) Cousin Bette. Des McAnuff Nunca te vayas sin decir te quiero (1998) Left Luggage. Jeroen Krabbe Whatever Happened to Harold Smith? (1999), Peter Hewitt...

r^{3}} dela dakigunez, m = ( 4 3 π r 3 ) ρ o {\displaystyle m=\left({\frac {4}{3}}\pi r^{3}\right)\rho _{o}} , erradioa Stokesen legetik ateratakoarekin ordezkatuz:...

ekintzak kontrolatzen ditu jokalariari laguntza emanez. The Last of Us: Left Behind deskargagarria den prekuelan pertsonaia jostagarri gisa berragertu...

lim n → + ∞ ( 1 + 1 n ) n {\displaystyle \lim _{n\to +\infty }\left(1+{\frac {1}{n}}\right)^{n}} Φ {\displaystyle \Phi } ("Urrezko" zenbakia 1,6180 ...):...

= T ( n π ) {\displaystyle \mathbf {t} _{\pi }=\mathbf {T} \left(\mathbf {n} _{\pi }\right)} Tentsio mekanikoa presio-unitateetan adierazten da, hau da...

d γ A a ∗ γ B b {\displaystyle K^{\circ }=\left({\frac {A_{C}^{c}*A_{D}^{d}}{A_{A}^{a}*A_{B}^{b}}}\right)=K*{\frac {\gamma _{C}^{c}*\gamma _{D}^{d}}{\gamma...

_{k=0}^{n}\left\lbrace {n \atop k}\right\rbrace ,\ \forall n\in \mathbb {N} .} Bigarren motako Stirling zenbakiak { n k } {\displaystyle \left\lbrace \textstyle...

(kontsulta data: 2026-04-20). ↑ (Ingelesez) Duvold, Kjetil. (2017). «When Left and Right is a Matter of Identity: Overlapping Political Dimensions in Estonia...

=\rho (\nu ,T)\mathrm {d} \nu =\rho (\nu ,T)\left|{\frac {\mathrm {d} \nu }{\mathrm {d} \lambda }}\right|\mathrm {d} \lambda ={\frac {8\pi \nu ^{2}k_{B}T}{c^{3}}}{\frac...

{(\gamma -1)\,mc^{2}}{h}}={\frac {mc^{2}}{h}}\left({\frac {1}{\sqrt {1-{\frac {v^{2}}{c^{2}}}}}}-1\right)} non ν {\displaystyle \nu } maiztasuna den eta...

Empathy". Annual Review of Psychology. 59 (1): 279–300. 2007, "Bonobos, Left & Right" Skeptic, (8 August 2007). 2006, Plotnik, Joshua M.; de Waal, Frans B...

et al.. (2001). «Research and development of an implantable, axial-flow left ventricular assist device: the Jarvik 2000 Heart.» Ann. Thorac. Surg. 71...

\left({\frac {\overline {A'B'}}{\overline {AB}}}={\frac {\overline {A'C'}}{\overline {AC}}}={\frac {\overline {B'C'}}{\overline {BC}}}\right)} Bi...

}}_{2}=\left({\frac {\mathbf {F} _{12}}{m_{1}}}-{\frac {\mathbf {F} _{21}}{m_{2}}}\right)=\left({\frac {1}{m_{1}}}+{\frac {1}{m_{2}}}\right)\mathbf {F}...

{\displaystyle {\tfrac {1}{\sqrt {3}}}\left(\left({\sqrt {-1}}\right)^{1/3}+\left({\sqrt {-1}}\right)^{-1/3}\right).} A priori, horrek zentzurik ez duela...

y ) | = | B M x B M y | {\displaystyle \left\vert OEM(x,y)\right\vert =\left\vert {BM_{x} \over BM_{y}}\right\vert } OEM indeferentzia-kurbaren malda...

= log b ⁡ ( x ) − log b ⁡ ( y ) {\displaystyle \!\,\log _{b}\left({\frac {x}{y}}\right)=\log _{b}(x)-\log _{b}(y)\,} - Berreketa baten logaritmoa berretzailearen...

{\displaystyle [\gamma _{0}]\cdot \left([\gamma _{1}]\cdot [\gamma _{2}]\right)=\left([\gamma _{0}]\cdot [\gamma _{1}]\right)\cdot [\gamma _{2}]} beraz, zatidura-multzoa...

{T_{2}}{T_{1}}}=\left({\frac {v_{1}}{v_{2}}}\right)^{k-1}} , T 2 T 1 = ( P 2 P 1 ) ( k − 1 ) / k {\displaystyle {\frac {T_{2}}{T_{1}}}=\left({\frac...

2 1 c 1 c 2 1 | {\displaystyle K=\left|{\begin{matrix}a_{1}&a_{2}&1\\b_{1}&b_{2}&1\\c_{1}&c_{2}&1\end{matrix}}\right|} Paralelogramoaren legea paralelogramo...

r → r ) = m g r g → {\displaystyle F=m_{gr}\left({\frac {GM}{r^{2}}}{\frac {\overrightarrow {r}}{r}}\right)=m_{gr}{\overrightarrow {g}}} Erorketa askeko...

{\displaystyle X_{s}(f)\ \triangleq \sum _{k=-\infty }^{\infty }X\left(f-kf_{s}\right)} Ikus daitekeenez, X s ( f ) {\displaystyle X_{s}(f)} funtzio periodiko...

{\displaystyle \lim _{x\to a}f(x)=L} da. ( 0 0 ) {\displaystyle \left({\frac {0}{0}}\right)} motako indeterminazioko lim x → 0 sen ⁡ ( x ) x {\displaystyle...

) = i ℏ ∂ ψ ∂ t ( x , t ) {\displaystyle \left(\alpha _{0}mc^{2}+\sum _{j=1}^{3}\alpha _{j}p_{j}\,c\right)\psi (\mathbf {x} ,t)=i\hbar {\frac {\partial...

biderkatzearen bera dena, a b = a ( 1 b ) {\displaystyle {\frac {a}{b}}=a\left({\frac {1}{b}}\right)} 1 elementu neutroak ez du batura aldatzen: a × 1 = a {\displaystyle...

{\displaystyle \left|{\begin{array}{ccc}x-x_{0}&x_{1}-x_{0}&x_{2}-x_{0}\\y-y_{o}&y_{1}-y_{0}&y_{2}-y_{0}\\z-z_{0}&z_{1}-z_{0}&z_{2}-z_{0}\\\end{array}}\right|=0.}...

{Qq}{r^{2}}}\,dr={\frac {Qq}{4\pi {\epsilon }_{0}}}\left({\frac {1}{r_{A}}}-{\frac {1}{r_{B}}}\right)} Lan elektrikoak egindako lana A-tik B-raino partikula...

{\sqrt {2\pi }}}}\mathrm {e} ^{\displaystyle -{\frac {1}{2}}\left({\frac {x-\mu }{\sigma }}\right)^{2}};-\infty <x<\infty } Estatistikan gehien erabiltzen...

) 1 + P ( s ) C ( s ) ) R ( s ) {\displaystyle Y(s)=\left({\frac {P(s)C(s)}{1+P(s)C(s)}}\right)R(s)} P ( s ) C ( s ) 1 + P ( s ) C ( s ) {\displaystyle...

(Ingelesez) Sabbagh-Khoury, Areej. (2023-08-22). Colonizing Palestine: The Zionist Left and the Making of the Palestinian Nakba. Stanford University Press ISBN 978-1-5036-3629-3...

= ? {\displaystyle HBP=\left\{{\begin{array}{rcl}{\frac {dy}{dx}}&=&f(x,y)\\y(x_{0})&=&y_{0}\\y(x_{i})&=&?\end{array}}\right.} Buruketa moduan pentsatu...

dibertsitate iluna ) {\displaystyle \log \left({\frac {\text{behatutako dibertsitatea}}{\text{dibertsitate iluna}}}\right)} . Formula honen bidez tokiko dibertsitatea...

Sparks, Fatman Scoop) 2017: "Destination Paradise" Nils van Zandt 2019: "Left Right" (Hardwell & Deorro & MAKJ) 2020: "Make Some Noise" (Wolfpack & Mike Bond...

) = 0.253 {\displaystyle P_{2}={\frac {1}{14(14-1)}}\left(0^{2}+2^{2}+6^{2}+4^{2}+2^{2}-14\right)=0.253} Taulan bertan azaltzen diren balio hauetan oinarrituz:...

ematen da: A = A 0 ( 1 − ν σ E ) 2 {\displaystyle A=A_{0}\left(1-\nu {\frac {\sigma }{E}}\right)^{2}} Non: A 0 {\displaystyle A_{0}\,} , hasierako azalera...

Bon Jovi. Bounce diskoaren bira bukatutakoan, 2003ko azaroan This Left Feels Right disko akustikoa atera zuten euren hamabi abesti arrakastatsuenen eraldaketekin...

= x 2 ] {\displaystyle \forall x_{1},x_{2}\in X\left[f(x_{1})=f(x_{2})\Rightarrow x_{1}=x_{2}\right]} ∀ x 1 , x 2 ∈ X [ x 1 ≠ x 2 ⇒ f ( x 1 ) ≠ f ( x...

g ( b j + ∑ i K i j ⊗ Y i ) {\displaystyle Y_{j}=g\left(b_{j}+\sum _{i}K_{ij}\otimes Y_{i}\right)} j {\displaystyle j} neurona baten Y j {\displaystyle...

2 L 2 ] = M L − 1 T − 2 . {\displaystyle [P]=\left[{\frac {{\text{M L T}}^{-2}}{{\text{L}}^{2}}}\right]={\text{M L}}^{-1}{\text{T}}^{-2}.} Partikula puntual...

{\displaystyle v(t)=V_{\mathrm {p} }\cos \left(2\pi ft+\phi \right)=\Re \left(V_{\mathrm {p} }e^{j2\pi ft}e^{j\phi }\right)} bertan j unitate imaginarioa ( −...

{1}{2}}\left(\nabla _{n}u_{m}+\nabla _{m}u_{n}\right)} u [ m ; n ] ≡ 1 2 ( ∇ n u m − ∇ m u n ) {\displaystyle u_{[m;n]}\equiv {\frac {1}{2}}\left(\nabla...

cos 2 ⁡ θ i {\displaystyle I=I_{0}{\frac {f}{f}}_{0}\left[1+{\frac {\lambda (f_{0}-f)}{2c}}\right]\cos ^{2}\theta _{i}} non f 0 {\displaystyle f_{0}} polarizatzailearen...

s^{2}=\left(1-{\frac {2GM}{c^{2}r}}\right)(c\Delta t)^{2}} − ( 1 + 2 G M c 2 r ) [ ( Δ x ) 2 + ( Δ y ) 2 + ( Δ z ) 2 ] {\displaystyle -\,\left(1+{\frac...

lim ( F ( x ) − F ( 0 ) x − 0 ) = 0 {\displaystyle \lim \left({\frac {F(x)-F(0)}{x-0}}\right)=0} dela. Beraz, F {\displaystyle F} deribagarria da x=0...

\left[{\frac {B_{0}^{2}A^{2}(L^{2}+R^{2})}{\pi \mu _{0}L^{2}}}\right]\left[{\frac {1}{z^{2}}}+{\frac {1}{(z+2L)^{2}}}-{\frac {2}{(z+L)^{2}}}\right]}...

V_{out}=V_{rf}\sin(\omega _{rf}t)\left[{\frac {4}{\pi }}\sum _{n=1,3,5...}{\frac {1}{n}}\sin(n\omega _{ol}t)\right]={\frac {V_{rf}4}{\pi }}\left[{\frac {1}{2}}[\sin(\omega...

z:=x} w h i l e ( z ≥ y ) l o o p {\displaystyle \textstyle {while}\left(z\geq y\right)\,\textstyle {loop}} z := z − y {\displaystyle z:=z-y} e n d l o o...

mugimenduarentzat soilik): 1 + z = ( 1 + v c ) γ . {\displaystyle 1+z=\left(1+{\frac {v}{c}}\right)\gamma .} Fenomenoa 1938. urtean ikusi zen lehen aldiz Herbert...

terminologian). 1 H z = [ 1 s ] {\displaystyle 1\,\mathrm {Hz} =\left[{\frac {1}{\mathrm {s} }}\right]} Maiztasuna (uhin batean) kalkulatzeko aukerako metodo bat...

{2m}}{h^{3}}}{\sqrt {\varepsilon }}d\varepsilon ={\frac {V}{3\pi ^{2}}}\left({\frac {2mE_{F}}{\hbar ^{2}}}\right)^{\frac {3}{2}}} non partikula askeentzako egoera dentsitatea...

{\displaystyle \left({\frac {1}{2}}\left(x-{\frac {1}{x}}\right)\right)^{2}+1=\left({\frac {1}{2}}\left(x+{\frac {1}{x}}\right)\right)^{2},} identitatearen...

g_{\mu \nu }dx^{\mu }dx^{\nu }=-c^{2}\left(1-{\frac {2GM}{c^{2}r}}\right)dt^{2}+\left(1-{\frac {2GM}{c^{2}r}}\right)^{-1}dr^{2}+r^{2}d\Omega ^{2}} non G...

\Rightarrow \ \ \left\{{\begin{array}{lcl}\Gamma _{00}^{0}=0\\\Gamma _{00}^{i}=-{\frac {1}{2}}\delta ^{ij}h_{00,j}\end{array}}\right.} Honela geratzen...

arabera: P ( x , t ) = | ψ ( x , t ) | 2 {\displaystyle P(x,t)=\left\vert \psi (x,t)\right\vert ^{2}} . Hori dela eta, uhin funtzioa nulua izan behar da...

2 R 1 + R 2 ) V s {\displaystyle V_{G}=\left({{R_{x}} \over {R_{3}+R_{x}}}-{{R_{2}} \over {R_{1}+R_{2}}}\right)V_{s}} Wheatstone zubiak, oso zehatza izan...

) − ln ⁡ p i ] {\displaystyle \ln \left({\frac {1}{p}}-1\right)=\sum _{i=1}^{N}\left[\ln(1-p_{i})-\ln p_{i}\right]} Utzi η = ∑ i = 1 N [ ln ⁡ ( 1 − p...

{\displaystyle L_{\mathrm {p} }=10\,\log _{10}\left({\frac {p}{p_{0}}}\right)^{2}=20\,\log _{10}\left({\frac {p}{p_{0}}}\right){\mbox{ dB}}}} non p 0 {\displaystyle...

ax^{2}+bx+c=a(x-\alpha )(x-\beta )=a\left(x-{\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}\right)\left(x-{\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}\right),}} Formula honi formula...

d N d t = r N ( 1 − N K ) {\displaystyle {\frac {dN}{dt}}=rN\left(1-{\frac {N}{K}}\right)} non r den populazioaren (N) hazkuntza erratioa eta K ingurunearen...

= v e ln ⁡ ( m 0 m f ) {\displaystyle \Delta v=v_{e}\ln \left({\frac {m_{0}}{m_{f}}}\right)} Non Δ v {\displaystyle \Delta v} suziriak lortu dezakeen...

(antzinako segundoa ( = eguna 60 × 60 ) {\displaystyle \left(={\frac {\text{eguna}}{60\times 60}}\right)} , eta ez orduarena, segundoaren definizio modernoagoarekin...

/ 2 ) {\displaystyle E={\frac {1}{8}}d\cdot g^{\left(3/2\right)}\cdot H^{2}\cdot h^{\left(1/2\right)}} , non d fluidoaren dentsitatea den. Teoria linealak...

I = ( n 2 − n 1 n 2 + n 1 ) 2 I o {\displaystyle I=\left({\frac {n_{2}-n_{1}}{n_{2}+n_{1}}}\right)^{2}I_{o}\!} non I o {\displaystyle I_{o}\!} intentsitate...

hurrengo aldaketa edukiko du | f 1 − f 2 | 2 {\displaystyle {\frac {\left\vert f1-f2\right\vert }{2}}} . Hau da, 300 Hz eta 304 Hz-eko bi uhin sinusoidal gainjartzen...

z ) {\displaystyle \left({\frac {\partial f}{\partial x}},{\frac {\partial f}{\partial y}},{\frac {\partial f}{\partial z}}\right)} eta denborarekiko...

( a u ) 3 = a u × u v × v 2 a = a 2 a = 1 2 . {\displaystyle \left({\frac {a}{u}}\right)^{3}={\frac {a}{u}}\times {\frac {u}{v}}\times {\frac {v}{2a}}={\frac...

Software Fundationerako sortutako GPL terminoa hartu nahian. Ingelesezko right eta left hitzek, eskuin eta ezker hurrenez hurren, copyright eta copyleft arteko...

− ( 2.3 ∗ R ∗ T n ∗ f ) l o g a i {\displaystyle E=E_{0}-\left({\frac {2.3*R*T}{n*f}}\right)loga_{i}} Bi era nagusitan eragin dezake tenperaturak pH-aren...

6 / 100 12 ) 12 ≈ 1 , 0617 = 1 + % 6 , 17 {\displaystyle \left(1+{\frac {6/100}{12}}\right)^{12}\approx 1,0617=1+\%6,17} Zehazki, urteko tasa baliokidea...

0}(w)=w^{1-a}\left({\frac {1+\lambda }{2w}}(1+w)\left[1+w+w\left(1+{\frac {1}{w^{2}}}-{\frac {2}{w}}{\frac {1-\lambda }{1+\lambda }}\right)^{1/2}\right]-1\right)^{a}}...

) = − 26 {\displaystyle \mathrm {round} \left({\frac {-415}{16}}\right)=\mathrm {round} \left(-25.9375\right)=-26} Deskodetze prozesua da orain arte egingakoaren...

V_{BA}=V_{B}-V_{A}=-\int _{r_{0}}^{B}{\vec {E}}\cdot d{\vec {l}}-\left(-\int _{r_{0}}^{A}{\vec {E}}\cdot d{\vec {l}}\right)} = ∫ B r 0 E → ⋅ d l → + ∫ r 0 A E → ⋅ d l → =...

1 1 x 2 y 2 1 | . {\displaystyle \left|{\begin{array}{ccc}x&y&1\\x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\\end{array}}\right|.} 3 dimentsiotako espazio batean,...

5776 X + . . . {\displaystyle t=\left({\frac {1}{\log _{2}(1+X/100)}}\right)\approx \left({\frac {69,31}{X}}\right)+0,3465-0,5776X+...} Hazkunde ekonomiko...

anti-immigration left leader set to win power in Denmark» The Observer ISSN 0029-7712. (kontsulta data: 2025-03-31). ↑ a b (Ingelesez) «Danish left veering right on...

Understand, Asshole Dub (20 Years of Dischord albumean) 2004: Straight Edge (Left of the Dial: Dispatches from the '80s Underground albumean) 2006: Filler...

{OliveGreen}Egia;}\end{array}}\right.\\{\color {Sepia}Bukatu\;Baldin}\;\\\end{array}}\right.\\{\color {Sepia}Bukatu\;For}\\\end{array}}\right.\\{\color...

x ′ ) = ( 1 + g x ′ c 2 ) d τ {\displaystyle d\tau (x')=\left(1+{\frac {gx'}{c^{2}}}\right)d\tau } Goian dauden erlojuak (jatorritik urrunago) azkarrago...

{\textstyle \mathbf {F} ={\frac {1}{4\pi \epsilon _{0}}}\left[{\frac {q_{1}q_{2}}{(r_{12})^{2}}}\right]{\hat {\mathbf {r} _{12}}}} ϵ 0 {\displaystyle \epsilon...

lim n → ∞ ( 1 + 1 n ) n {\displaystyle e=\lim _{n\to \infty }\left(1+{\frac {1}{n}}\right)^{n}} Adierazpen horri binomioaren teorema aplikatuz, e {\displaystyle...

979 × 10 11   m . {\displaystyle 1\ \mathrm {AU} =\left({\frac {GM}{4\pi ^{2}}}{\rm {yr}}^{2}\right)^{\frac {1}{3}}\approx 1,\!495\,979\times 10^{11}\...

{\displaystyle v=\left\vert {\boldsymbol {v}}\right\vert =\left\vert {\operatorname {d} {\boldsymbol {r}} \over \operatorname {d} \!t}\right\vert ={\operatorname...

{\displaystyle \left\langle \left.{\frac {d\phi _{\lambda }}{d\lambda }}\right\vert _{\lambda =0},{\frac {dL}{d{\dot {\mathbf {q} }}}}\right\rangle =v_{1}p_{1}+...

n + r ⋅ q 2 … q n p 1 . : {\displaystyle p_{2}\ldots p_{m}=\left(d+{r \over p_{1}}\right)q_{2}\ldots q_{n}=d\cdot q_{2}\ldots q_{n}+{r\cdot q_{2}\ldots...

exist three major camps in libertarian thought: right-libertarianism, socialist libertarianism, and left-libertarianism; the extent to which these represent...

\mathbb {N} }} segida guztietarako ( f ( x n ) ) n ∈ N {\displaystyle \left(f(x_{n})\right)_{n\in \mathbb {N} }} segida f ( c ) {\displaystyle f(c)} punturantz...

∂ σ i j {\displaystyle g(\sigma _{ij},\xi _{k})=\left(\sum _{i,j}\sigma _{ij}\varepsilon _{ij}\right)-f(\sigma _{ij},\xi _{k}),\qquad \varepsilon _{ij}={\frac...

eskalarra 0 izango da, cos ⁡ ( π 2 ) = 0 {\displaystyle \cos \left({\dfrac {\pi }{2}}\right)=0} delako. Biderketa eskalarra negatiboa izan daiteke bi bektoreek...

"arcs":[[0,1]],"properties": {"name": "Left_Polygon" }}, {"type": "Polygon", "arcs":[[2,-1]],"properties": {"name": "Right_Polygon" }} ] }, "one-line": {...

Planck-en konstante laburbilduaren unitatetan ( ℏ ) {\displaystyle \left(\hbar \right)} adierazia. Fermioiak dira-eta, Pauliren elkarrezintasunaren printzipioagatik...

^{2}=-c^{2}\,dt^{2}+a(t)^{2}\left({\frac {dr^{2}}{1-\kappa r^{2}}}+r^{2}\left(d\theta ^{2}+\sin ^{2}\theta \,d\phi ^{2}\right)\right)} Koordenatu kohigikorren...

{dx}{ax+b}}={\frac {1}{a}}\int {(ax+b)^{-1}}adx={\frac {1}{a}}\ln \left|ax+b\right|} Azalera (zirkuluarena): Bolumena (laukizuzenarena): Bigarren mailako...

^{2}\theta d\phi )^{2}+{\frac {\sin ^{2}\theta }{\rho ^{2}}}\left[(r^{2}+a^{2})d\phi +a\ dt\right]^{2}+{\frac {\rho ^{2}}{\Delta }}dr^{2}+\rho ^{2}d\theta...

3 ) {\displaystyle {\boldsymbol {F}}=m{\boldsymbol {a}}\left(1-{\frac {v^{2}}{c^{2}}}\right)^{-{\frac {3}{2}}}\qquad ({\mbox{3}})} Kontuan hartu behar...

\scriptstyle {\frac {L_{V_{\ast }}}{L_{V_{\odot }}}}=10^{0.4\left(M_{V_{\odot }}-M_{V_{\ast }}\right)}} ↑ Gainazaleko grabitatea zuzenean Newtonen grabitazio...

] = [ v R ] = L ⋅ T − 1 L = T − 1 . {\displaystyle [\omega ]=\left[{\frac {v}{R}}\right]={\frac {{\text{L}}\cdot {\text{T}}^{-1}}{\text{L}}}={\text{T}}^{-1}...

Victoria; Kampwirth, Karen. (2010-11-01). Radical Women in Latin America: Left and Right. Penn State Press ISBN 978-0-271-04247-3. (kontsulta data: 2023-11-12)...

definitua: B = { x ∈ A : x ∉ f ( x ) } . {\displaystyle B=\left\{\,x\in A:x\not \in f(x)\,\right\}.} Azpimultzo hori ezin dela A {\displaystyle A} ko elementu...

kalkulatzen da c luzera: (left) c 2 = h 2 + u 2 {\displaystyle c^{2}=h^{2}+u^{2}\,} Baina h luzera ere horrela kalkulatzen da: (left) h 2 = a 2 − ( b − u )...

\Rightarrow \left\vert \alpha -R_{n}\right\vert <{\frac {1}{2q_{n}^{2}}}} edo | α − R n + 1 | < 1 2 q n + 1 2 {\displaystyle \left\vert \alpha -R_{n+1}\right\vert...

(20{\text{buru}})\\&={\frac {1}{2^{20}}}\left[{\binom {20}{14}}+{\binom {20}{15}}+\cdots +{\binom {20}{20}}\right]={\frac {60,\!460}{1,\!048,\!576}}\approx...

parametroa: q = − H − 2 ( d H d t + H 2 ) {\displaystyle q=-H^{-2}\left({\frac {dH}{dt}}+H^{2}\right)} Denbora luzean zehar q positibotzat hartu zen; honek iradokitzen...

f ( a + b 2 ) {\displaystyle \int _{a}^{b}f(x)dx\sim (b-a)f\left({\frac {a+b}{2}}\right)} Eta errorea hau da: ( b − a ) 3 24 f ( 2 ) ( ξ ) {\displaystyle...

N\rangle =k_{\text{B}}T{\frac {1}{\mathcal {Z}}}\left({\frac {\partial {\mathcal {Z}}}{\partial \mu }}\right)_{V,T}={\frac {1}{\exp((\varepsilon -\mu )/k_{\text{B}}T)-1}}}...

aurkitzeko ondoko ekuazioa ebatzi ( A − λ I ) v = 0 {\displaystyle \left(A-\lambda I\right)\mathbf {v} =\mathbf {0} } eta v-ren osagaiak lortu. Adibide honetan...

ψ ⟩ = ( | + ⟩ + | − ⟩ ) / 2 {\displaystyle |\psi \rangle =\left(|+\rangle +|-\rangle \right)/{\sqrt {2}}} moduan adierazi dezakegu. Honela, Bornen arauei...

g ( H C O 3 − H 2 C O 3 ) {\displaystyle pH=pKa+log\left({\frac {HCO_{3}^{-}}{H_{2}CO_{3}}}\right)} Karbono dioxidoa, metabolismo zelularraren produktu...

intentsitatea: R = ( n 0 − n S n 0 + n S ) 2 , {\displaystyle R=\left({\frac {n_{0}-n_{S}}{n_{0}+n_{S}}}\right)^{2},} non n0 eta nS baitira, hurrenez hurren, lehen...

M·LT − 2 L·LT − 1 = ML − 1 T − 1 . {\displaystyle [\eta ]=\left[{\frac {F_{\text{f}}}{kv}}\right]={\frac {{\text{M·LT}}^{-2}}{{\text{L·LT}}^{-1}}}={\tex...

24-25 base-pareko bi ertzek mugaturikoa, eskumako ertza (“Right Border”) eta ezkerreko ertza (“Left Border”) bezala ezagunak. Ertz hauek Ti plasmido ezberdinen...

January 2009). "Delusional misidentifications and duplications: Right brain lesions, left brain delusions". Kontsultatu: http://www.neurology.org/content/72/1/80...

K B T ϵ ] − 1 / 2 {\displaystyle \lambda _{D}=\left[{\frac {2e^{2}c_{\infty }}{K_{B}T\epsilon }}\right]^{-1/2}} Hemengo λ D {\displaystyle \lambda _{D}}...

daiteke: [ θ ] = [ l R ] = m m = m 0 . {\displaystyle [\theta ]=\left[{\frac {l}{R}}\right]={\frac {\text{m}}{\text{m}}}={\text{m}}^{0}.} Duela gutxi arte...

arabera zehazten da: 10 × ( 1 − b a ) {\displaystyle 10\times \left(1-{\frac {b}{a}}\right)} Horrela, b berdina duen galaxia esferiko batentzat, zenbakia...

= 4 {\displaystyle \left\lbrace \!\!\!{\begin{array}{rl}3x+2y+1z=&\!\!\!1\\2x+0y+1z=&\!\!\!2\\1x+1y+2z=&\!\!\!4\end{array}}\right.} Zeina matrize moduan...

{\boldsymbol {F}}_{12}=-G{\frac {m_{1}m_{2}}{{\left\vert {\boldsymbol {r}}_{2}-{\boldsymbol {r}}_{1}\right\vert }^{2}}}{\boldsymbol {u}}_{12},} grabitazio...

absolutuak emandako d ( x , y ) = | x − y | {\displaystyle d(x,y)=\left\vert x-y\right\vert } distantzia funtzioarekin eta orokortuz, n {\displaystyle n}...

data: 2022-05-23). ↑ Petrov, Kristian. (2019-03-04). «‘Strike out, right and left!’: a conceptual-historical analysis of 1860s Russian nihilism and its...

{\displaystyle E_{n}=\left\{0={\frac {0}{n-1}},{\frac {1}{n-1}},{\frac {2}{n-1}},...,{\frac {n-2}{n-1}},{\frac {n-1}{n-1}}=1\right\}} n {\displaystyle n}...

{\displaystyle \left\{{\begin{array}{rccl}x&=&(2\cdot 52)&+\lambda \cdot {\frac {10}{2}}\\y&=&(-1\cdot 52)&-\lambda \cdot {\frac {6}{2}}\end{array}}\right.\forall...

adierazten du: κ = ( 1 + h R ) 2 − 1 {\displaystyle \kappa ={\sqrt {\left(1+{\frac {h}{R}}\right)^{2}-1}}} Kurbadura hori kurbaduraren erradio angeluarraren elkarrekikoa...

Work for Food Underworld – Dubnobasswithmyheadman Van Halen – Live: Right Here, Right Now Whigfield – Whigfield X Japan – Art of Life Yngwie J. Malmsteen...

erlatibo espezifiko h = ( 1 − e 2 ) μ a {\displaystyle h={\sqrt {\left(1-e^{2}\right)\mu a}}} Energia orbital espezifikoa ε = − μ 2 a {\displaystyle \varepsilon...

eszentrikotasun bektorearen magnitude gisa: e = | e | {\displaystyle e=\left|\mathbf {e} \right|} non: e eszentrikotasunaren bektorea den. Orbita eliptikoetarako...

↑ kleptocracy. . ↑ Samuels, L.K.. (2019). Killing History: The False Left-Right Political Spectrum. Freeland Press, 484 or.. ↑ Greenberg, Paul. (1989)...

hau da: P = ⟨ p ( t ) ⟩ = U ef I ef cos ⁡ φ , {\displaystyle P=\left\langle p(t)\right\rangle =U_{\text{ef}}I_{\text{ef}}\cos \varphi ,} eta bertan ageri...

=\lim _{n\rightarrow \infty }\left(1+{\frac {1}{2}}+{\frac {1}{3}}+{\frac {1}{4}}+\cdots +{\frac {1}{n}}-\ln(n)\right).} Bestalde, Eulerren interes deigarrienetako...

Warren M.. (1998-10-27). «Electrical Conduction Between the Right Atrium and the Left Atrium via the Musculature of the Coronary Sinus» Circulation...

politikoekin hitz egin zuen, eta gaiari buruzko liburu tematiko bat idatzi zuen, Right-Wing Women. Lehen senarrarengandiko genero-indarkeria jasan ondoren, literatura...

{\displaystyle W={\frac {1}{2}}CV^{2}={\frac {1}{2}}{\frac {\varepsilon A}{d}}\left(Ed\right)^{2}={\frac {1}{2}}\varepsilon AdE^{2}={\frac {1}{2}}\varepsilon E^{2}({\text{Eremu...

90 ∘ _ = V /   β _ X L /   90 ∘ _ {\displaystyle {\vec {I}}=\left({V \over X_{L}}\right)_{/\!\!\!{\underline {\ \beta -90^{\circ }}}}={V_{/\!\!\!{\underline...

d N d t = r N ( 1 − N K ) {\displaystyle {\frac {dN}{dt}}=rN\left(1-{\frac {N}{K}}\right)\qquad \!} non r baita biztanleriaren hazkunde-tasa (N), eta...

h_{\alpha }(a_{1},a_{2},...,a_{n})=\left({\dfrac {a_{1}^{\alpha }+a_{2}^{\alpha }+...+a_{n}^{\alpha }}{n}}\right)^{1/\alpha }} α {\displaystyle \alpha...

editoreek: “The regime of the Weimar Republic was challenged from both right and left in Germany throughout the early 1920s, and there was widespread fear...

Dance» CTVNews (kontsulta data: 2022-06-02). ↑ (Ingelesez) «Calgary teen left mark on So You Think You Can Dance» torontosun (kontsulta data: 2022-06-02)...

{\displaystyle {\displaystyle y=f({\vec {w}}\cdot {\vec {x}})=f\left(\sum _{j}w_{j}x_{j}\right)}} Non w → {\displaystyle {\displaystyle {\vec {w}}}} pisu-bektore...

angelua den eta d s = | d r | {\displaystyle {\text{d}}s=\left\vert {\text{d}}{\boldsymbol {r}}\right\vert } izanik. Definizio horretan oinarriturik, honelaxe...

deritzo (SP). S P v ∝ | A ( v ) | 2 {\displaystyle SP_{v}\propto \left\vert A(v)\right\vert ^{2}} Garrantzitsua da gogoratzea ausazko uhin edo estokastiko...

Dreams - Gordon Company, Universal - Lawrence Gordon, Charles Gordon My Left Foot - Ferndale Films, Granada, Raidio Teilifis Eireann - Noel Pearson 1990...

+ 4 t 2 )   e − 2 1 + 4 t 2 ( x − k 0 t ) 2 {\displaystyle \ \ \left|\Psi (x,t)\right|^{2}={\sqrt {\frac {2}{\pi (1+4t^{2})}}}\ e^{-{\frac...

{\displaystyle {\begin{cases}x'=\gamma (x-vt)\\y'=y\\z'=z\\t'=\gamma \left(t-{\frac {vx}{c^{2}}}\right)\end{cases}}} non c {\displaystyle c} argiaren abiadura da ...

stop). LF: ezkerreko kanpoaldea (Left fielder). CF: erdialdeko kanpoaldea (Center fielder). RF: eskuineko kanpoaldea (Right fielder). Erdi sarrera bakoitzaren...

_{1}}}{\hat {\tau _{2}}})\left\{U_{4}({\vec {r}})+U_{5}({\vec {r}})({\hat {\sigma _{1}}}{\hat {\sigma _{2}}})+U_{6}({\vec {r}})S_{12}\right\}} , non r = r 1 −...

diren. C = B log 2 ⁡ ( 1 + S N ) {\displaystyle C=B\log _{2}\left(1+{\frac {S}{N}}\right)} Bit-tasa netoa ≤ kanalaren gaitasuna {\displaystyle {\text{Bit-tasa...

Gaur egungo egoera globalaren isla handi bat izanik, The Migrants Have Left lanak, adibidez, lehen pertsonengan zentratutako marrazkiak hankaz gora jartzen...

k ( T ) = A ⋅ e ( − E a R T ) {\displaystyle k(T)=A\cdot e^{\left(-{\frac {Ea}{RT}}\right)}} k ( T ) {\displaystyle k(T)} : Erreakzioaren abiadura konstantea...

GREEN PYRAMID. (Piramide berdea.) Person: There were five blocks to the left of the box then. (Orduan bost bloke zeuden kuxaren ezkerraldean.) Computer:...

kasuan d l = | d x → d λ | d λ {\displaystyle dl=\left\vert {\frac {d{\vec {x}}}{d\lambda }}\right\vert {}d\lambda } non λ {\displaystyle \lambda } parametro...

esleitzen dien. Adibidez, zenbaki errealetako [ 0 , 1 ] {\displaystyle \left[0,1\right]} tartearen Lebesgueren neurria da haren luzera, hitzaren eguneroko...

Lurrarentzat, Hill erradioa R H = a ( m 3 M ) 1 3 {\displaystyle R_{H}=a\left({\frac {m}{3M}}\right)^{\frac {1}{3}}} da, non m Lurraren masa den, a unitate astronomiko...

x , y , z ) ∂ z d x ⋅ d y ⋅ d z {\displaystyle dF_{z}=\left[\rho (x,y,z)-\rho (x,y,z+dz)\right]dx\cdot dy\simeq -{\frac {\partial \rho (x,y,z)}{\partial...

{\boldsymbol {r}}(t)=(v_{0x}{t}+x_{0}){\boldsymbol {i}}+\left(-{\frac {1}{2}}g{t^{2}}+v_{0y}t+y_{0}\right){\boldsymbol {j}}} Ekuazio bektorial hau osagaietan...

nosemanual, one-foot manual, one-foot nosemanual, one-wheel manual, left manual, right manual, penguin manual, handstand manual… besteak beste. Manual akrobaziak...

Naomi(November 28, 2011). "Capitalism vs. the Climate: What the right gets — and the left doesn't — about the revolutionary power of climate change". The...

Jonathan; Tucker, Joshua A.; Bonneau, Richard. (2015-10). «Tweeting From Left to Right: Is Online Political Communication More Than an Echo Chamber?» Psychological...

j = 0 2 ( − 1 ) 2 − j ( 2 j ) j 4 = 7. {\displaystyle S(4,2)=\left\{{4 \atop 2}\right\}={\frac {1}{2!}}\sum _{j=0}^{2}(-1)^{2-j}{2 \choose j}j^{4}=7...

m ] d M z d x = V y {\displaystyle {\frac {dV_{y}}{dx}}=-q\ \left[{\frac {N}{m}}\right]\qquad {\frac {dM_{z}}{dx}}=V_{y}} Artikulu nagusia: «Hidrostatika»...

From back to front and from left to right :  Auguste Piccard, Émile Henriot, Paul Ehrenfest, Édouard Herzen, Théophile de Donder, Erwin Schrödinger, Jules-Émile...